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likoan [24]
3 years ago
9

Help with 21 and not 22 please

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0
So the 170 is the area
and the formula for that is A=lw
so you have a length of 15.5.     
Put those in and you get 170.5=15.5w.
you divide 170.5 by 15.5 and get 11.
the Width is 11.
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Tanya's car will go 45 meters on 7 gallons. Tanya wants to know how fuel efficient the car is. Please help by computing the rati
grigory [225]

Answer:

5 meters : 1 gallon

fuel efficiency of Car is 7 meters per gallons

Step-by-step explanation:

Given Tanya car goes 45 meters on 7 gallons.

In terms of ratio  of distance traveled and fuel consumed

45 meters : 7 gallons

since both 45 and 7 are multiple of 7 dividing both side by 7

45/7 meters : 7/7 gallons

5 meters : 1 gallon

Thus, fuel efficiency of Car is 7 meters per gallons.

3 0
3 years ago
HELLLLPP 6(X+7) for x=9. Answer choices/ 1. 12. 2. 42. 3. 96. 4. 16
Lina20 [59]

It's 96

6(9+7)

6(16)

6*16

=

<u>96</u>

7 0
2 years ago
Write this number in expanded form 73,489
mart [117]

the answer is 70,000+3,000+400+80+9

3 0
3 years ago
Find the median mode range and any outliers. Then describe the data using them 77777,88,555,6,99,10101010,12
umka2103 [35]

Answer:

The median = 5

The mode  = 7

Range = 5

Outliers= None

Step-by-step explanation:

The median is the  value of the middle term.

The median is that value which divides the data into two equal halves.

7,7,7,7,7,8,8,5,5,5,6,9,9,10,10,10,10,12

There are 18 terms . So the middle term would be 9th term value= 5

The mode is the value which is repeated the most. = 7

Range is the difference between the highest and lowest value.= 12- 7= 5

The interquartile range, IQR= q3 - q1 where q3= 10 and q1= 7

IQR= 10 −7=3

The inner fences can be found out by

q1−(1.5*IQR) and q3+(1.5*IQR)

=7−(1.5*3) and 10+(1.5*3)

Inner fences: 2.5 and 14.5

The outer fences are q1−(3*IQR) and q3+(3*IQR)

=7−(3*3) and 10+(3*3)

Outer fences: -2 and 19

So if there are any outliers in this data set, they will either be less than -2 or greater than 19. But there are no outliers.

6 0
3 years ago
What is the solution of ?<img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%20x-7%3D%5Cfrac%7B3%7D%7B4%7D%20x%2B14" id="Tex
Nonamiya [84]

Combine the terms by multiplying into a single fraction.

\bf{\dfrac{5}{2}x-7=\dfrac{3}{4}x+14   }

Find the common denominator.

\bf{\dfrac{5x}{2}-7=\dfrac{3}{4}x+14   }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x(-7)}{2}=\dfrac{3}{4}x+14   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3}{4}x+14   }

Combine the multiplied terms into a single fraction

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+14   }

Find the common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x}{4}+\dfrac{4\cdot14}{4}    }

Combine fractions with the lowest common denominator.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+4\cdot14}{4}   }

Multiply the numbers.

\bf{\dfrac{5x-14}{2}=\dfrac{3x+56}{4}   }

Eliminate the denominators of the fractions.

\bf{4\cdot\dfrac{5x-14}{2}=4\cdot\dfrac{3x+56}{4}   }

Cancel the multiplied terms that are in the denominator.

\bf{2(5x-14)=3x+56}

To distribute.

\bf{10x-28=3x+56 }

Add 28 to both sides.

\bf{10x-28+28=3x+56+28 }

Simplify

\bf{10x=3x+84 }

Subtract 3x from both sides.

\bf{10x-3x=3x+84-3x }

Simplify

\bf{7x=84 }

Divide both sides by the same factor.

\bf{x=\dfrac{84}{7} }

Simplify

\bf{x=12 \ \ \ === > \ \ \ Answer}

↓

<h3>Verification</h3>

Let x=12.

  1. \bf{\dfrac{5}{2}\times12-7=\dfrac{3}{4}\times12+14   }
  2. \bf{\dfrac{5\times12}{2}-7=\dfrac{3}{4}\times12+14   }
  3. \bf{\dfrac{60}{2}-7=\dfrac{3}{4}\times12+14   }
  4. \bf{30-7=\dfrac{3}{4}\times12+14   }
  5. \bf{30-7=\dfrac{3\times12}{4}+14   }
  6. \bf{30-7=\dfrac{36}{4}+14   }
  7. \bf{30-7=9+14   }
  8. \bf{23=9+14 }
  9. \bf{23=23}

Checked ✅

3 0
2 years ago
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