Answer: 14 Hours
Step by step:
Start by listing the information from the problem.
The spaceship's average speed is 8 kilometers per second. You can write this as a fraction in two ways:
8 km
1 sec
or
1 sec
8 km
.
The spaceship needs to travel 403,200 kilometers.
The problem asks how long it will take the spaceship to travel 403,200 kilometers. The spaceship is moving at a rate of
1 sec
8 km
. Multiply so that the kilometers cancel out. The result will be in seconds.
403,200km
1sec
8km
=
403200kmsec
8km
=50400 sec
Now you know it will take the spaceship 50,400 seconds to reach the moon, but the problem asks about hours. So, convert the seconds to hours. If you don't know how many seconds are in an hour, you can first convert the seconds to minutes.
There are 60 seconds in 1 minute, so multiply by
1 min
60 sec
. The result will be in minutes since the units of seconds cancel out.
50,400sec
1min
60sec
=
50400secmin
60sec
=840 min
Now convert 840 minutes to hours. There are 60 minutes in 1 hour, so multiply by
1 hr
60 min
.
840min
1hr
60min
=
840minhr
60min
=14 hr
It will take the spaceship 14 hours to get to the moon.
Answer:
QR(3), RS(3), PQ(3), ST(11), RP(6), RT(14), SP(9), QT(17)
Step-by-step explanation:
The diagram is not shown, but we assume the points are in the sequence ...
P, Q, R, S, T
Since QR = RS, R is apparently the midpoint of QS, So ...
23. QR = 6/2 = 3
24. RS = QR = 3
25. PQ = QR = 3
26. ST = PT -PQ -QS = 20 -3 -6 = 11
27. RP = PQ +QR = 3 +3 = 6
28. RT = RS +ST = 3 +11 = 14
29. SP = PQ +QS = 3 +6 = 9
30. QT = QS +ST = 6 +11 = 17
107.95
The area of a trapezoid is as follows:
A =
A and B are the lengths of the parallel lines of trapezoids. The parallel lines in this problem are 3.5 and 9.2. After adding those and dividing by 2, we multiply 17 to find the area of the trapezoid. (This is also shown in the attached picture)
The sum of 1/3 plus 1/6 is 1/2
