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zalisa [80]
3 years ago
11

Determine the number of bytes necessary to store an uncompressed binary image of size 4000 × 3000 pixels

Computers and Technology
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:  1,500,000 bytes.

Explanation:

If we assume that we have an image of 4000 pixels (picture elements) wide, by 3000 pixels height, a complete uncompressed image will be represented by 4000*3000= 12,000,000 pixels.

Now, if we are talking of a binary image, this means that each pixel will have, as a maximum, two possible values, so we will need only one bit per pixel.

This means that  we will need to store 12,000,000 bits.

As we know, 1 byte=8 bits.

So, we will need 12,000, 000/8 bytes ⇒ 1,500,000 bytes in order to store an uncompressed binary image of size 4000 x 3000 pixels.

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A hardware supplier manufactures three kinds of​ clamps, types​ A, B, and C. Production restrictions force it to make 10 more ty
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Answer:

A = 120

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Solution:

As per the question:

Manufacturer forced to make 10 more type C clamps than the total of A and b:

10 + A + B = C                (1)

Also, 3 times as many type B as type A clamps are:

A = 3B                             (2)

The total no. of clamps produced per day:

A + B + C  = 330              (3)

The no. of each type manufactured per day:

Now, from eqn (1), and (3):

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2A + 2B = 320

A + B = 160                       (4)

Now, from eqn (2) and (4):

3B + B = 160

B = 40

Since, A = 3B

A = 3\times 40

A = 120          

Put the values of A and C in eqn (3):

120 + 40 + C = 330

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What type of system converts between plaintext and ciphertext?
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