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stepan [7]
3 years ago
8

Solve -vp+40<95 for v

Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0

-vp+40<95

subtract 40 from each side

-vp < 55

divide by -p (which flips the inequality) assuming p>0

v > -55/p


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You throw two four-sided dice. Let the random variable X represent the maximum value of the two dice. Compute E(X). Round your a
Troyanec [42]

Answer:

E(X)=3.125

Step-by-step explanation:

We are given that two four sided dice.

Then , the sample space

{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(3,4),(4,1),(4,2),(4,3),(4,4)}

Total number of outcomes=16

Let the random variable X represent the maximum value of the two dice

Outcomes                            X                                 P(X)

(1,1)                                          1                                 1/16

(1,2),(2,1),(2,2)                                   2                        3/16

(1,3),(2,3),(3,1),(3,2),(3,3)                    3                           5/16  

(1,4),(3,4) ,(2,4),(4,1),(4,2),(4,3),(4,4)    4                            7/16

Using the probability formula

P(E)=\frac{Favorable\;outcomes}{Total\;number\;of\;outcomes}

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E(X)=\sum_{i=1}^{n}x_iP(x_i)

E(x)=1(1/16)+2(3/16)+3(5/16)+4(7/16)

E(x)=\frac{1+6+15+28}{16}

E(x)=\frac{50}{16}=3.125

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3 years ago
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8 0
3 years ago
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Answer:

1. x = ±9

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Step-by-step explanation:

According to the questions,

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3 years ago
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