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brilliants [131]
3 years ago
6

What is the radius of 34.54

Mathematics
2 answers:
Tema [17]3 years ago
7 0
The radius is <span>5.497211734394065

</span>
jonny [76]3 years ago
3 0
5.497211734394065 is the radius of 34.54
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Please answer this correctly
Mnenie [13.5K]

Answer: 30 grams

Step-by-step explanation:

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150 - 120 = 30

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The linear equation y=2x represents the cost y for x pounds of apples.Which ordered pair lies on the graph of the equation?
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Simplify <br> 3 2/3 - 2 3/4 =
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Answer: 11/12

Step-by-step explanation:

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3 2/3=(3*3+2)/3=11/3

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6 0
3 years ago
The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha
Xelga [282]

Answer:

The average value of f over the interval [-2,5] is \frac{10}{7}.

Step-by-step explanation:

Let suppose that function f is continuous and integrable in the given intervals, by integral definition of average we have that:

\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6 (1)

\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20 (2)

By Fundamental Theorems of Calculus we expand both expressions:

\frac{F(3)-F(-2)}{3-(-2)} = -6

F(3) - F(-2) = -30 (1b)

\frac{F(5)-F(3)}{5-3} = 20

F(5) - F(3) = 40 (2b)

We obtain the average value of f over the interval [-2, 5] by algebraic handling:

F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)

F(5) - F(-2) = 10

\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}

\bar f = \frac{10}{7}

The average value of f over the interval [-2,5] is \frac{10}{7}.

4 0
2 years ago
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