Answer: The bacteria transformed with this particular plasmid will form white colonies on the plates containing ampicillin and Xgal.
Explanation: The lacZ gene produces an enzyme called β-galactosidase which is responsible for the breakdown of lactose into glucose and galactose. The lacZ gene is one of the three genes (the other two being lacA and lacY) of the lac operon which is responsible for the transport and mechanism of lactose in E. coli and many other bacteria.
In recombinant DNA technology, when a plasmid is to be used to transform a host cell, such markers are used to help screen the transformed cells from the ones that have not taken up the plasmid. Xgal present in the plates is an artificial substrate which is hydrolyzed by
β-galactosidase into 5-bromo-4-chloro-indoxyl which will dimerize and oxidise into 5,5'-dibromo-4,4'dichloro-indigo. This is a blue pigment which will give blue color to the bacterial cells. Introducing a DNA fragment in this lacZ gene will make it non-functional so it will not be able to produce the enzyme.
Therefore, when a bacterial cell is transformed with a plasmid containing ampicillin resistance gene and a DNA fragment introduced in the lacZ gene and then grown on plates containing ampicillin and Xgal, white colored colonies will appear. The white colonies will show the bacterial cells that have successfully taken up the plasmid with the DNA fragment incorporated in the lacZ gene as this will render the gene non-functional and will not produce β-galactosidase which will breakdown Xgal to give blue colonies. Since the plates contain ampicillin, only the bacterial cells that have been successfully transformed with the plasmid ( the ones that have the DNA fragment and the ones without it) will grow as the ampicillin resistance will give them resistance against ampicillin in the plates. The bacterial cells that have not taken up the plasmid will not be resistant to ampicillin and will not form colonies on the plate.
This is called blue-white screening which is used to identify successfully transformed host cells. A picture of this is given in the attachment, taken from the following website:
https://www.mun.ca/biology/scarr/Blue_&_White_Colonies.html
<span>They bind messenger RNA and transfer RNA to synthesize polypeptides and proteins.</span>
Answer:
Experiment 4. Relaxed, the drug will stop the calcium so that it does not act on the troponin
Experiment 5. Contraction: In order for the muscle to relax, the actin and tropomyosin union must occur.
Experiment 6. Relaxation: the release of the actin-myosin complex occurs with consumption of ATP, thus it slides and generates contraction, by adding a hydrolyzable analog, this reaction is avoided giving rise to a prolonged actin-myosin binding which leads to relaxation while last effect.
Experiment 7. Ca2 + Contraction is very necessary so that during muscle contraction troponin can be extracted.
DNA is a nucleic acid molecule that undergoes a replication process to form a new daughter strand. The blue segment is the parental strand, and the yellow is the daughter strand.
<h3>What is replication?</h3>
Replication is the process of the central dogma that duplicates the copy of the parent strand into new daughter strands. The two helixes of the parent strand get separated to make the complimentary copy of the new strand.
The daughter DNA is semi-conservative and are complementary structure made from the duplication of the parent strand with the help of the replication enzymes.
Therefore, the daughter strands are the semi-conservative copies of the parental strand.
Learn more about replication here:
brainly.com/question/16464230
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