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kirill [66]
4 years ago
5

What is a interval on a graph

Mathematics
1 answer:
poizon [28]4 years ago
4 0
"An interval on a graph is the number between any two consecutive numbers on the axis of the graph. If one of the numbers on the axis is 50, and the next number is 60, the interval is 10. The interval remains the same throughout the graph."
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Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!
andriy [413]

remember that you can do anything to an equation as long as you do it to both sides

remember the distributive property: a(b+c)=ab+ac

also commutative property of addition: a+b=b+a

so

6(6x-2)+8(1-5x)=2x

distribute

6(6x-2)=6(6x)+6(-2)=36x-12

8(1-5x)=8(1)+8(-5x)=8-40x


36x-12+8-40x=2x

group like terms

36x-40x-12+8=2x

add like terms

-4x-4=2x

add 4x to both sides to get x by itself

4x-4x-4=2x+4x

0-4=6x

-4=6x

divide both sides by 6

-4/6=(6x)/6

-2/3=x(6/6)

-2/3=x(1)

-2/3=x

x=-2/3

the solution is x=-2/3

3 0
3 years ago
Read 2 more answers
Which Proportion is correct?
Nikolay [14]

Answer:

sorry but i need the points <3

Step-by-step explanation:

7 0
3 years ago
What is the scale factor of AABC to AXYZ?
antoniya [11.8K]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
i have a bag of trail mix. One half of the bag is peanuts, one quarter of the bag is chocolate candies and one quarter of the ba
Sonja [21]
It’s easier to see with actual numbers therefore, since you are not given a total, say there are 20
Which means, 10 are peanuts, 5 are chocolate candies and 5 are dried fruit.
Out of the 20 options, there are 5 that are the chocolate candies.
This means there is a 5 in 20 chance you will pick the chocolate candies.
5/20 = ¼ (i.e. the likelihood to pick one is the same as the fraction of chocolate candies the bag contains)
8 0
3 years ago
Find the volume of the solid under the plane 3x+2y−z=0 and above the region enclosed by the parabolas y=x^2 and x=y^2.
Yuri [45]

The region in the <em>x</em>-<em>y</em> plane is the set of points

R=\{(x,y)\mid0\le x\le 1,x^2\le y\le\sqrt x\}

The height of the solid falls between the <em>x</em>-<em>y</em> plane (for which <em>z</em> = 0) and the equation of the plane, <em>z</em> = 3<em>x</em> + 2<em>y</em>.

So the volume is

\displaystyle\int_0^1\int_{x^2}^{\sqrt x}\int_0^{3x+2y}\mathrm dz\,\mathrm dy\,\mathrm dx

=\displaystyle\int_0^1\int_{x^2}^{\sqrt x}(3x+2y)\mathrm dy\,\mathrm dx

=\displaystyle\int_0^1(3x^{3/2}+x-3x^3-x^4)\,\mathrm dx

=\displaystyle\frac65+\frac12-\frac34-\frac15=\boxed{\dfrac34}

5 0
3 years ago
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