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pickupchik [31]
3 years ago
8

Someone help me fast please. Given the diagram below and DE∣∣∣∣KL, find FE and FL.

Mathematics
1 answer:
stealth61 [152]3 years ago
8 0

Answer:

Part 1) The length of segment FE is 10 units

Part 2) The length of segment FL is 4.8 units

Step-by-step explanation:

we know that

Triangle FED and triangle FKL are similar by AA Similarity Postulate

Part 1) Find FE

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

\frac{DE}{KL}=\frac{FE}{FK}

substitute the given values

\frac{15}{6}=\frac{FE}{4}

FE=15(4)/6\\FE=10\ units

Part 2) Find FL

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

\frac{DE}{KL}=\frac{FD}{FL}

substitute the given values

\frac{15}{6}=\frac{12}{FL}

FL=6(12)/15\\FL=4.8\ units

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Luden [163]
If you would like to know what percent is 27.30 of 36.40, you can calculate this using the following steps:

x% of 36.40 = 27.30
x/100 * 36.40 = 27.30
x/100 = 27.30/36.40
x = 27.30/36.40 * 100
x = 75

To check: 75% * 36.40 = 75/100 * 36.40 = 27.30

The correct result is 75%. 
7 0
3 years ago
A pan of warm water (46∘ Celsius) was put in a refrigerator. After 15 minutes, the water's temperature was 27∘ C; 15 minutes aft
Cloud [144]

Answer:

The refrigerator was at around 13 ∘C

Step-by-step explanation:

Newton's Law of Cooling:

The rate of change of a body temperature  (amount of heat loss/time of loss) is directly proportional to the difference between its own temperature and the surroundings.

\frac{T(t2)-T(t1)}{t2-t1} = -h (T(t2) - Tenv)

T ⇒ temperature

t ⇒ time

Tenv ⇒refrigerator temperature

\frac{T(t2)-T(t1)}{t2-t1} ⇒ rate of change of he temperature

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We have 3 points:

time (minutes) - Temperature (∘ C)

0 (when the pan was put in the refrigerator) - 46

15 (after 15 minutes) - 27

30 (15 minutes after the first 15 minutes) - 19

\frac{27 - 46}{15 - 0} = -h (27 - Tenv)

\frac{19 - 27}{15 - 0} = -h (19 - Tenv)

Now we have a system of two equations and two variables

\frac{-19}{15} = -h (27 - Tenv)\\ \frac{19}{15} = h (27 - Tenv)\\ \frac{19}{15(27 - Tenv)} = h

\frac{19 - 27}{15 - 0} = -h (19 - Tenv)\\\frac{-8}{15} = -h (19 - Tenv)\\\frac{8}{15} = h (19 - Tenv)\\\frac{8}{15} = \frac{19}{15(27 - Tenv)} (19 - Tenv)\\8(27 - Tenv) = 19 (19 - Tenv)\\216 - 8 Tenv = 361 - 19 Tenv\\19 Tenv - 8 Tenv = 361 - 216\\11 Tenv = 145 \\Tenv = 145/ 11\\Tenv = 13. 18

The refrigerator was at around 13 ∘C

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3 years ago
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lana66690 [7]
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Answer:

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