Answer:
<u>1. Mean = 342.7 (Rounding to the nearest tenth)</u>
<u>2. Median = 167.5 </u>
<u>3. Mode = There isn't a mode for this set of numbers because there isn't a data value that occur more than once. </u>
Step-by-step explanation:
Given this set of numbers: 107, 600, 115, 220, 104, 910, find out these measures of central tendency:
1. Mean = 107 + 600 + 115 + 220 + 104 + 910/6 = <u>342.7</u> (Rounding to the nearest tenth)
2. Median. In this case, we calculate it as the average between the third and the fourth element, this way:
115 + 220 =335
335/2 = <u>167.5 </u>
3. Mode = <u>There isn't a mode for this set of numbers because there isn't a data value that occur more than once. All the data values occur only once.</u>
Answer:k=1,k=-2,k=
Step-by-step explanation:
Given two vectors


Distance between them is given by

squaring both side



k=1

angle between u and v is 90 i.e. orthogonal

=0
2+k=0
k=-2

angle between u & v is 





=0
k=
5.3×10^5=53×10^4
53×10^4+3.8×10^4
=56.8×10^4
=5.68×10^5. Hope it help!
1.5/d+34 is the inverse operation
Answer is 56 because on his 3rd exam he got 57 word per minute, since he got 57 he can take out 7 of those words and he would still have 50. Remember the extra 7 words we have. Then you would calculate how many more words he needs to get to fifty on his other exams which are 4,6,and 3. Add these 3 and you get 13. Remember we still have that extra 7. We pick 56 with the extra 7 it would be 63. You can take out 13 words to fill in the other exams and u would still be left with 50.
Therefor your answer is 56.