An individual who develops and implements plans to exploit the internet for marketing and sales opportunities!
Answer:
import java.util.Scanner;
public class num2 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count =0;
int total = 0;
System.out.println("Enter the numbers");
int num = in.nextInt();
while(num!=-1){
total = total+num;
count++;
System.out.println("Enter the next number");
num = in.nextInt();
}
//Compute the average
double average = (double) total/count;
//Outputs
System.out.println("Total count of numbers entered "+(count));
System.out.println("Sum of the numbers "+total);
System.out.printf("Average is %.2f ",average);
}
}
Explanation:
- Using java programming language
- Import scanner class to receive user input
- declare variables count and total and initialize to zero
- Prompt user to enter numbers
- Use a while statement with the condition while(num!=-1)
- Within the while body keep prompting user to enter a number, increase count and update total
- when -1 is entered the loop breaks and average is calculated
- Use printf() method to print average to 2 decimal places.
The program is correct: at the beginning, product = 0. Then, we start summing Y to that variable, and we sum Y exactly X times, because with each iteration we increase Count by 1, and check if Count=X so that we can exit the loop.
Answer:
import random
score = 0
for i in range(5):
num1 = random.randint(1, 100)
num2 = random.randint(1, 100)
prompt = "What is " + str(num1) + "+" + str(num2) + "?"
answer = int(input(prompt))
result = (num1, num2)
if answer == result:
print("Well done!")
score += 1
else:
print("incorrect")
print("Your score was", score)
Explanation:
Your error is on <em>line 7</em>, where you are providing multiple arguments to the input function, instead of 1.
One way to solve this is to create a variable prompt and concatenate all strings and variables within that variable to use for the input.
Answer:
what I'm confused ???????
Explanation:
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