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3 years ago

5

Which best describes the relationship between the line that passes through the points (1, –6) and (3, –2) and the line that pass

es through the points (4, 8) and (6, 12)

1 answer:

vodka [1.7K]3 years ago

4 0

Answer:

The two lines intersect (intersecting lines) at point (1, 2) on a graph

Step-by-step explanation:

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What is the solution of the inequality x^3+3x^2>7x+6

sveta [45]

Answer:

<u><em>x>2</em></u>

Step-by-step explanation:

<u><em>x3+3x2=7x+6</em></u>

<u><em>x3+3x2−(7x+6)=7x+6−(7x+6)</em></u>

<u><em>x3+3x2−7x−6=0</em></u>

<u><em>(x−2)(x2+5x+3)=0</em></u>

<u><em>x−2=0 or x2+5x+3=0</em></u>

<u><em>x=2 or x=−0.6972243622680054 or x=−4.302775637731995</em></u>

<u><em>x<−4.302776</em></u>

<u><em>−4.302776<x<−0.697224</em></u>

<u><em>−0.697224<x<2</em></u>

<u><em>x>2(Works in original inequality)</em></u>

3 0

2 years ago

Does (40,0) make the equation y=0 true?

Basile [38]

Use the substitution method for y=0

(40,0)

y=0

0=0

Answer: (40,0) It does make the equation y=0 true

5 0

3 years ago

Read 2 more answers

The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m

larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words $=\frac{13!}{4\times 2!\times 3!}=64,864,800$

When M's are together . considering 2 M's as one

therefore there are $\frac{12!}{3\times 2!\times 3!}=9,979,200$

No of ways $=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600$

(b)No of ways such that M's are separated by at least 2 letters

at least 2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

$=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

$=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

$=45738000$

7 0

3 years ago

PLS HELP ME!!!! I WILL MARK U!!!!!<br><br> MATH!!!!

erica [24]

Answer:

-38

Step-by-step explanation:

y=2

z=-17

yz-y^2

(2)(-17)-(2)^2

-34-4

-38

4 0

3 years ago

INSTRUCTION: Solve the matrix multiplication on the space provided.

Tema [17]

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>☝</em><em>☝</em><em>✌</em><em>✌</em><em>✌</em>

6 0

3 years ago