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steposvetlana [31]
3 years ago
13

Please solve this problem 5y+30=5()

Mathematics
1 answer:
nadya68 [22]3 years ago
7 0
First you would subtract 30 from both sides 
they divide each side by 5 to get -7 
y =-7 
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Alistair has a rectangular picture measuring 8 inches by 7 inches. He makes a frame for the picture, shown by the shaded area in
nydimaria [60]
<span>You are given a rectangular picture measuring 8 inches by 7 inches. Also, Alistair wants this to be framed and that the total area is 34 square inches. The width of the frame is x inches. To solve the dimension of the frame with value of x we have:

We have to assume that x here will be equal to all sides of the frame and so, using the area of the rectangle, we can model the equation like this:
A = LW (where A is the area, L is the length and W is the width)
36 = (8 - x)(7 - x)
36 = 56 - 8x - 7x + x</span>²
<span>x</span>² - 15x +20 = 0 → model of our equation and in quadratic form

x² - 15x + 20 = 0
using a calculator, x = 1.48 inches
<span>
3.Use the equation you created in part A to find the width of the picture frame</span>
7 0
3 years ago
What is the solution set for
lana [24]
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5 0
3 years ago
Write 6^8 • 6^7 as a single power
taurus [48]
<h3><u>Write 6^8 • 6^7 as a single power:</u></h3>

6^8 \times 6^7 = 6^{15}

<em><u>Solution:</u></em>

Given that,

We have to write 6^8 • 6^7 as a single power

Given is:

6^8 \times 6^7

<em><u>Use the following law of exponent</u></em>

a^m \times a^n = a^{m+n}

When, the base is same, powers gets added

Therefore,

6^8 \times 6^7 = 6^{8+7}\\\\6^8 \times 6^7 = 6^{15}

Thus the given is written as a single power

3 0
3 years ago
What is the simplified form of the following expression? (n5)(n2)
Hatshy [7]
In exponent multiplication, When the bases are the same you ADD the power so it is n^7
5 0
3 years ago
What are the numbers of pi \pi help due Friday
ohaa [14]

Answer: 3.14285714.....

<u>Step-by-step explanation:</u>

pi is  \dfrac{22}{7}

.\quad \underline{\ 3.14285714}\\.\ 7)22.0000000\\.\ \ \underline{-21}\\.\qquad 10\\.\qquad \underline{- 7}\\.\qquad\ \ 30\\.\quad\ \ \ \underline{-28}\\.\qquad \ \ \ 20\\.\quad\ \quad \underline{-14}\\.\qquad \quad \ \ 60\\.\qquad \quad \underline{-56}\\.\qquad \qquad \ 4

Thiis is a non-terminating and non-repeating decimal.

8 0
3 years ago
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