we know that
if ABC is an isosceles right triangle
then
side AC=side BC
angle A=angle B=45 degrees
cos B=adjacent side angle B/hypotenuse
adjacent side angle B=BC
hypotenuse=AB------> 18 ft
angle B=45 degrees
cos 45°=(√2)/2
so
cos 45°=BC/AB-------> solve for BC
BC=AB*cos 45-------> BC=18*(√2)/2------> BC=9√2 ft
AC=BC--------> AC=9√2 ft
the answer part 1) is
the exact lengths of the two sides, AC and BC is
AC=9√2 ft
BC=9√2 ft
Part b) Find the Area of triangle ABC
Area=b*h/2-------> AC*BC/2-----> (9√2)*(9√2)/2--------> 81 ft²
the answer part b) is
the area of triangle ABC is equal to 81 ft²
Answer:
3x√5 + 6√(10x) + 5√(3x) + 10√6
Step-by-step explanation:
__
The applicable rules of roots are ...
(√a)(√b) = √(ab)
√(ab²) = b√a
9514 1404 393
Answer:
C. 161.459 square feet
Step-by-step explanation:
In feet, the dimensions of the pool are ...
(5 m)(3.28084 ft/m) = 16.4042 ft
(3 m)(3.28084 ft/m) = 9.84252 ft
Then the area of the pool is ...
(16.4042 ft)(9.84252 ft) = 161.458666584 square feet
about 161.459 square feet
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<em>Additional comment</em>
If you consider that a square meter is slightly less than 11 square feet, the pool area can be estimated to be (5 m)(3 m)(11 ft²/m²) = 165 ft². This is close enough to point you to the correct answer choice.
The answer is A. If you plug 12 into x and 6 into y, it would make sense.
12=2(6)
2×6=12
12=12
Hope this helped even though you have the answer :)
