The correct answer for the question that is being presented above is this one: "A. Quadrilateral KJFG was rotated 90° counterclockwise around the origin and then translated 8 units down." Quadrilateral KJFG is congruent to quadrilateral K ' J ' F ' G '.
Answer:
(x-1)²/49 + (y+3)²/16.51 = 1
Step-by-step explanation:
vertex (8,-3) Foci (6.7,-3) center (h,k) = (1,-3) , major axis parallel to x axis
a is the distance of the vertex from the center, and c is the distance of the foci from the center. b is semi-minor axis
b² = a² - c² Ellipse equation: (x-h)²/a² + (y-k)²/b² = 1
a = 8-1 = 7 c = 6.7 - 1 = 5.7
b² = 7² - 5.7² = 16.51
Ellipse equation: (x-1)²/49 + (y- -3)²/16.51 = 1 i.e. (x-1)²/49 + (y+3)²/16.51 = 1
Answer:correct answers are:
A.m<JPX=90°
B.XY & JK form right angles
E. JP=KP
F.XY⊥JK
Step-by-step explanation:
hope this helps
Answer:
0
Step-by-step explanation:
This equation is in "vertex form," meaning that you can identify the vertex and other features of the graph from the equation.
y = a(x -h)² +k . . . . . the vertex is (h, k); the vertical scale factor is "a"
Comparing to your equation, you see ...
a = -1/2, h = 3, k = -1
The vertex is (h, k) = (3, -1). The vertical scale factor is negative.
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This tells you the graph opens downward (the scale factor is negative), and the vertex (maximum point) is below the x-axis. (It has a negative y-coordinate.)
Because it start below the x-axis and goes down from there, the graph does not intersect the x-axis. There are zero (0) x-intercepts.