Can someone do D PLEASE
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Answer:
The lower quartile is 23.5
The upper quartile is 32.5
The interquartile range is 9
Step-by-step explanation:
The given data set is 20, 22, 25, 28, 29, 30, 32, 33, 34.
The data set is already sorted in ascending order.
The middle number of this data set is called the median.
Therefore the median is 29.
The median divides the data set into two halves.
The lower half is
20, 22, 25, 28
The median of the lower half is the lower quartile.
The upper half is 30, 32, 33, 34
The median of the upper half is the upper quartile.
The interquartile range is given by
Answer:
a. see attached
b. H(t) = 12 -10cos(πt/10)
c. H(16) ≈ 8.91 m
Step-by-step explanation:
<h3>a.</h3>The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.
The function describing the height will be ...
H(t) = 12 -10cos(πt/10)
The graph of it is attached.
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<h3>b. </h3>See part a.
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<h3>c.</h3>The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.
H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983
The height of the rider 6 seconds after passing the top will be about 8.91 m.
