Can someone do D PLEASE

How do I create a histogram for the data?

Andrews [41]

Answer:

Group by buckets and use that information to make your histogram.

Step-by-step explanation:

When you make a histogram you need to group elements into buckets, and out of those buckets make your histograms. You could for example take the mean or the median of groups and out of that information make the histogram. That is your decision.

For example that you have

JM 85

JM 73

so the mean between 85 and 73 is 79 , so in your histogram the height of JM would be 79.

To summarize, you group by buckets and use that information to make your histogram.

4 0

4 years ago

Two numbers have difference of 0.7 and a sum of 1. What are the numbers?

Readme [11.4K]

We can solve this by setting up 2 equations. We can use any letters like. For now, I'll use x and y.
So now we know that    x - y = 0.7   and    x + y = 1.
Now we can eliminate one of the letters by adding or subtracting one equation from the other. I am going to eliminate y by adding the two together (the y and the -y cancel).
This gives us   2x = 1.7,    and so x = 1.7 ÷ 2 = 0.85
Finally, we can substitute x for 0.85 back into one of the original equations to figure out what y equals. I'm going to use   x + y = 1.
So now we have   0.85 + y = 1,    so y = 1 - 0.85 = 0.15

The numbers, therefore, are 0.85 and 0.15 (you can check by using the other equation).

Hope this helps!

5 0

4 years ago

A teacher gives a test to a large group of students. The results are closely approximated by a normal curve. Teh mean is 73, wit

zavuch27 [327]

Answer:

The bottom for an A is 75. Round to the nearest whole number as needed.

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Let X the random variable that represent the scores on this case, and for this case we know the distribution for X is given by:

$X \sim N(\mu=73,\sigma=7)$

And let $\bar X$ represent the sample mean, the distribution for the sample mean is given by:

$\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})$

2) The bottom for an A is _____. Round to the nearest whole number as needed.

And we want the top 5.5% of the scores, so we need a value a such that:

$P(X>a)=0.055$ or $P(X$

We need on the right tail of the distribution a value a that gives to us 94.5% of the area below and 5.5% of the area above. Both conditions are equivalent.

Let's use the condition $P(X$ , the best way to solve this problem is using the z score with the following formula:

$z=\frac{x-\mu}{\sigma}$

So we need a value from the normal standard distribution that accumulates 0.945 of the area on the left and 0.055 on the right. This value on this case is 1.598 and we can founded with the following code in excel:

"=NORM.INV(0.945,0,1)"

If we apply the z score formula to our case we have this:

$P(X$

So then based on the equalities we have this:

$\frac{a-73}{7}=1.598$

And if we solve for a we got:

$a=(7*1.598) +73=84.186$

So then we need a score of 84.186 rounded to the nearest whole number 75 or higher in order to get an A

8 0

3 years ago

8x{[(7+4)x2] - [(11-7)x4]}

Anni [7]

PEMDAS
P - Parentheses (or other grouping symbols)
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction

$8x[(7+4)x^2] - [(11-7)x^4]\\ \\ 8x[(11)x^2] - [(4)x^4] \\ \\ 8x[11x^2] - [4x^4] \\ \\ 88x^3 - 4x^4 \\ \\ -4x^4+88x^3$

If you then want to go on to factor it, your answer would be $-4x^3(x-22)$

8 0

4 years ago

Read 2 more answers

Find all the points having an x-coordinate of 4 whose distance from the point (-2,-1) is 10

Marta_Voda [28]

$A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\the\ distance\ between\ A\ and\ B:\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\A(-2;-1);\ B(4;\ y);\ d=10\\\\subtitute\\\\\sqrt{(4-(-2))^2+(y-(-1))^2}=10\\\\\sqrt{(4+2)^2+(y+1)^2}=10\\\\\sqrt{6^2+(y+1)^2}=10\\\\\sqrt{36+(y+1)^2}=10\ \ \ |square\ both\ sides\\\\36+(y+1)^2=10^2\\\\36+(y+1)^2=100\ \ \ |subtract\ 36\ from\ both\ sides\\\\(y+1)^2=64\iff y+1=-\sqrt{64}\ or\ y+1=\sqrt{64}\\\\y+1=-8\ or\ y+1=8\ \ \ \ |subtract\ 1\ from\ both\ sides\\\\y=-9\ or\ y=7$

$Answer:{\boxed{(4;-9)\ or\ (4;\ 7)}$

4 0

3 years ago