Answer:
= −0.26
= 0.4219
Step-by-step explanation:
Given:
Sample1: 98.1 98.8 97.3 97.5 97.9
Sample2: 98.7 99.4 97.7 97.1 98.0
Sample 1 Sample 2 Difference d
98.1 98.7 -0.6
98.8 99.4 -0.6
97.3 97.7 -0.4
97.5 97.1 0.4
97.9 98.0 -0.1
To find:
Find the values of and
d overbar ( ) is the sample mean of the differences which is calculated by dividing the sum of all the values of difference d with the number of values i.e. n = 5
= ∑d/n
= (−0.6 −0.6 −0.4 +0.4 −0.1) / 5
= −1.3 / 5
= −0.26
s Subscript d is the sample standard deviation of the difference which is calculated as following:
= √∑( - )²/ n-1
=
√
= √ (−0.6 − (−0.26 ))² + (−0.6 − (−0.26))² + (−0.4 − (−0.26))² + (0.4 −
(−0.26))² + (−0.1 − (−0.26))² / 5−1
=
=
=
= 0.4219
= 0.4219
Subscript d represent
μ represents the mean of differences in body temperatures measured at 8 AM and at 12 AM of population.
Step-by-step explanation:
Answer:
5. 40
Step-by-step explanation:
(14) +(4x+6) = 8x
14 + 4x+ 6 = 8x
20 = 8x - 4x
4x = 20
x = 5
RT = 8x
= 8 * 5....since x = 5
= 40
Answer:
57 °
Step-by-step explanation:
Complementary angles = 90 °
Since, Your angle don't have ∠ [ ] Then Let let "C" and "y"
Thurs, C = 12x- 3 and y = 7x - 2
It is given that angles r and s are complementary angles. Two angles are complementary if they add up to 90 degrees. This means the sum of measures of angle r and angle s must be 90 degrees. So,
c + y = 90
12x - 3 + 7x - 2 = 90
19x - 5 = 90
19x = 95
x = 95/19
x = 5
Using the value of x in expression or r, we get:
c = 12x - 3 = 12(5) - 3 = 60 -3 = 57 degrees.
So measure of angle c is 57 degrees.
Hence, the ∠ is 57 °
[RevyBreeze]
Answer:
ASA
Step-by-step explanation:
ASA because 2 corresponding angles are congruent. The two triangles also share a common side, so it is congruent to itself. Therefor, it is ASA.
So it is essentially 80% of the original price , so what i would do is divide it by 8 and then times it by 10 to get the original price , in this case it will be 50/8 (6.25) and then times 6.25 by 10 which will give you the original price of $62.50<span />
