Answer:
452.39 mi^2
Step-by-step explanation:
A = πr^2
A = π (12mi)^2
A = 452.39 mi^2
Please mark Brainliest :D
Please mark Brainliest :D
your marks 9 my marks 5
Step-by-step explanation:
1/2 of 14 = 7
7 + 2 = 9
14 - 9 = 5
so your marks are 9 and mine are 5
Hope this helped ..
To solve this problem you must apply the proccedure shown below:
1- The formula for calculate the area of this rectangle is:
Where 
is the length and 
is the heigth.
2. Let's call identify the heigth with the variable 
.
3. If the length is 
longer than the heigth, you have:
4. Therefore, you can write the following polynomial expression:
5. If you know the value of the heigth, you can susbstitute it into the polynomial expression shown above and you will obtain the area.
Therefore, the answer is: 
We'll have to add up all the fractions.
First, find the LCM of the denominators.
To do this, we'll use the listing method.
4: 4, 8, 12, 16, 20, 24, 28, 32, 36, all the way to 140.
5: 5, 10, 15, 20, 25, 30, 35, all the way to 140.
7: 7, 14, 21, 28, 35, 42, 49, all the way to 140.
So, 140 is the Least Common Multiple.
Multiply the numerator of 1 as many times you multiplied 4 to get to 140, which is 35.
1 x 35 = 35.
Multiply the numerator of 2 as many times you multiplied 5 to get to 140, which is 28.
2 x 28 = 56
Multiply the numerator of 3 as many times you multiplied 7 to get to 140, which is 20.
3 x 20 = 60.
So: 35/140 + 56/140 + 60/140
=35/140 + 116/140
=151/140
=1 11/140
So, the swimmer swam 1 and 11/140th of a mile.
I'm going to assume that you're discussing the linear function y = mx + b. If that's not it, please provide more information on the function you're studying.
y = mx + b has a graph that is the straight line through (0,b) with slope m.
y = m(x-5) + b has a graph which is parallel to the previous graph, but intersects the x-axis at a different point.
Examples: start with y = mx + b
Suppose we have y = 3x + 2 to work with
The graph intersects the y-axis at (0,2). It intersects the x-axis where y=0=3x+2, or at x = -2/3 => (-2/3, 0)
Now modify y = 3x + 2 by replacing "x" with "x-5." the graph of this "new" function f(x) = 3(x-5) + 2 is parallel to the original graph, but lies 5 units to the right of the original graph. Both lines have slope 3.
In this case, if x increases by 4 (as your problem states), y will increase by 3(4), or 12, units.
If we go back to y = m(x-5), we see that the graph of this function intersects the x-axis at x=5, and this graph has the (unknown) slope m.
If x increases by 4, y increases by (m)(4), or 4m.
