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ratelena [41]
3 years ago
14

Solve for j. -1j+1>2 Please help.

Mathematics
1 answer:
prohojiy [21]3 years ago
6 0
You can use photomath for this
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Show all work. What are the zeros of the function?<br> f(x) = 2x^2 − 8x − 10
vivado [14]
(2x² - 8x - 10) ÷ 2 = 0
x² - 4x - 5 = 0
x² + x - 5x - 5 = 0
x(x+1) - 5(x+1) = 0
(x+1)(x-5) = 0
x+1 = 0 or x-5 = 0
x = -1 or x= 5

S = {-1;5}

3 0
3 years ago
Olga tried to solve an equation step by step
LuckyWell [14K]

Answer:

made a mistake in step 3

Step-by-step explanation:

from step2; 1/3k=15 then making k the subject ,k=15*3 so the value of k will be 45

3 0
3 years ago
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Find the value of 33 - (4)(2). 1,10,19,46
Charra [1.4K]

Given: 33 - (4)(2)

33 - (4)(2) = 33  - 8

= 25

Hence, the value is 25.

5 0
3 years ago
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11. Which matrix represents the system of equations below?
dimulka [17.4K]

Answer:

\left[\begin{array}{cccc}-12&-13&13&|15\\7&-10&-3&|11\\7&14&5&\:\:\:|-5\end{array}\right]

Step-by-step explanation:

The system of equations is;

-12x-13y +13z =15

7x-10y-3z = 11

7x+14y +5z = -5

The coefficient matrix is \left[\begin{array}{ccc}-12&-13&13\\7&-10&-3\\7&14&5\end{array}\right]

The constant matrix is \left[\begin{array}{c}15\\11\\-5\end{array}\right]

The augmented matrix is \left[\begin{array}{cccc}-12&-13&13&|15\\7&-10&-3&|11\\7&14&5&\:\:\:|-5\end{array}\right]

4 0
3 years ago
Factor out the greatest common factor<br> 15x^2-21x<br> ^=exponent
gavmur [86]

Answer:

3x

Step-by-step explanation:

3x(5x-7)

brainliest!

4 0
3 years ago
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