No, they forgot to switch variable labels after solving for the independent variable...
y=-8x+4
y-4=-8x
(y-4)/-8=x
Now that you have solved for the independent variable x, you switch the variable labels...
y=(x-4)/-8
f^-1(x)=(x-4)/-8 which should really be rewritten as:
f^-1(x)=(4-x)/8 :P
Answer:
Height of the building = 115.4 ft.
Step-by-step explanation:
Height of building = AB + 46.4 + CD + 30.5
By applying Pythagoras theorem in ΔABP,
(26)² = (10)²+ (AB)²
676 - 100 = AB²
AB² = 576
AB = 24 ft
By applying sine rule in ΔCDE,
cos(60°) = 
CD = CE × 
CD = 
CD = 14.5 ft
Total Height = 24 + 46.4 + 14.5 + 30.5
= 115.4 ft
Answer:
1. Precise
2.Both
3.Precise
5.Neither
Step-by-step explanation:
Accuracy is the closeness of a measured value to a standard value.
Precision is the closeness of two or more measurements to each other.
1.The norm is 45 sit-ups in a minute.The students did, 64, 69,65 and 67. Values are not accurate compared to standard value 45.
Values are precise
Answer--Precise
2. Average score is 89.5
Scores are 89,93,91,87
Values are precise i.e a difference of 2 from each score
Values are accurate because the average score is 90 thus compared to the known average score of 89.5 they are accurate.
Answer-Both
3. Yesterday temperature=89
Tomorrow=88
Next day=90
Average =75
Values are precise i.e. difference of ± 1°
Values are not accurate compared to the average temperatures of 75 F
Answer---Precise
5. The jar contained 568 pennies
The 6 people guessed the numbers as
735,209,390,300,1005, 689
The values are not precise
The values are not accurate
Answer---Neither
Answer:
Lacy is 13 and Jack is 52
Step-by-step explanation:
In 3 years their ages will add up to 71 so you have to subtract 6 as there are two of them to get 65. Lacy's age is represented by x and since Jack is 4 times older his age is represented by 4x. So added together their age is 5x. So 5x=65. Then 65/5=13. So 13=x. So Lacy is 13 and Jack is 52 as 13x4 is 52.
Answer:
155.3 m
Step-by-step explanation:
<u>We have:</u>
θ: is the angle measured from the vertical = 75 °
v = is the speed of the submarine = 10 m/s
t = 1 min
The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:
<u>Where:</u>
d: is the distance traveled by the submarine in 1 minute
x: is the deep to find
The distance, d, is:
Now, the deep is:
Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.
I hope it helps you!
