3 years ago

Wich is the first operation performed in evaluating

Mathematics

1 answer:

stellarik [79]3 years ago

3 0

The first operation performed while evaluating would be to do the parenthesis

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CAN SOMEONE PLEASE HELP!!!

IceJOKER [234]

Answer:

162 and 18

Step-by-step explanation:

use fractions make x 180 and do 9/10x and 1/10x

5 0

2 years ago

The possible answers are 1, 3, 4, and 5

nexus9112 [7]

Answer:

Step-by-step explanation:

pls mark me as brainliest

6 0

2 years ago

Read 2 more answers

74.94×103= because the number 10³ has ? zeros when it is written without an exponent.

horsena [70]

Answer:

74940, three

Step-by-step explanation:

74.94 × 10³

74.94 × 1000

74940

6 0

2 years ago

A jacket usually sells for $69.00. If the jacket is 30% off, and sales tax is 8%, what is the total price of the jacket, includi

Ivan

$52.16
30% of 69 is 20.7.
69-20.7= $43.30
8% of 43.3 is 3.864.
43.3+3.864= $52.164
round down due to the 4.
$52.16

7 0

3 years ago

In the equation (x^2+y)^5, what is the coefficient of the term x^4y^3? what is the coefficient of the same term in the expansion

lys-0071 [83]

$\displaystyle
(x+y)^n=\sum_{k=0}^n\binom{n}{k}x^{n-k}y^k$

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$\displaystyle
(x^2+y)^n=\sum_{k=0}^n\binom{n}{k}x^{2n-2k}y^k\\
n=5\\
k=3\\\\\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdor5}{2}=10$

It's 10.

----------------------------------------------------

$\displaystyle
(3x^2+y)^n=\sum_{k=0}^n\binom{n}{k}(3x)^{2n-2k}y^k=\sum_{k=0}^n\binom{n}{k}\cdot 3^{2n-2k}\cdot x^{2n-2k}y^k\\\\
n=5\\
k=4\\\\
\binom{5}{3}\cdot3^{2\cdot5-2\cdot4}=10\cdot3^{2}=10\cdot9=90$

It's 90

6 0

3 years ago