Of the new cars in a car dealer's lot, 1 in 6 are white. Today, 4 cars were sold.

A drawer contains 6 black neckties, 2 white neckties,4 red neckties,2 maroon neckties and 2 blue neckties. One necktie is picked

kogti [31]

A) The probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) The probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) The probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E ) the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

Step-by-step explanation:

Here, the total number of black neckties = 6

The total number of white neckties = 2

The total number of red neckties = 4

The total number of maroon neckties = 2

The total number of blue neckties = 2

The number of times the experiment is repeated = 300

A ) P(Picking a white tie) = $\frac{\textrm{Total number of white ties}}{\textrm{Total Bow ties}}$

= $\frac{2}{16} = \frac{1}{8}$

So, the probability of picking a white ONCE is 1/8.

Now, as the experiment is REPEATED 300 times with replacement.

So, the probability of picking a white tie 300 times = $(\frac{1}{8}) ^{300}$

B) P(Picking a BLUE tie) = $\frac{\textrm{Total number of blue ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a blue ONCE is 1/8.

Hence, the probability of picking a blue tie 300 times = $(\frac{1}{8}) ^{300}$

C) P(Picking a Red tie) = $\frac{\textrm{Total number of Red ties}}{\textrm{Total Bow ties}} = \frac{4}{16} = \frac{1}{4}$

So, the probability of picking a red ONCE is 1/4.

Hence, the probability of picking a red tie 300 times = $(\frac{1}{4}) ^{300}$

D) P(Picking a Black tie) = $\frac{\textrm{Total number of black ties}}{\textrm{Total Bow ties}} = \frac{6}{16} = \frac{3}{8}$

So, the probability of picking a red ONCE is 3/8.

Hence, the probability of picking a black tie 300 times = $(\frac{3}{8}) ^{300}$

E) P(Picking a maroon tie) = $\frac{\textrm{Total number of maroon ties}}{\textrm{Total Bow ties}} = \frac{2}{16} = \frac{1}{8}$

So, the probability of picking a maroon ONCE is 1/8.

Hence, the probability of picking a maroon tie 300 times = $(\frac{1}{8}) ^{300}$

F) P(Picking a NOT whiten tie) = 1 - P( picking a white tie)

$= 1-(\frac{1}{8} ) = \frac{8-1}{8} = (\frac{7}{8} )$

So, the probability of NOT picking a white ONCE is 7/8.

Hence, the probability of NOT picking a white tie 300 times = $(\frac{7}{8}) ^{300}$

4 0

3 years ago

Delta makes 12-volt car batteries. These batteries are known to be normally

blondinia [14]

Answer:

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

Step-by-step explanation:

Step(i):-

Given that the sample size n =12 -volt car batteries

Let 'X' be a Random variable in a normal distribution

Given that mean of the normal distribution = 45 months

Given that the Standard deviation of the normal distribution = 8months

Step(ii):-

Let X₁ = 3 years = 12 × 3 = 36 months

$Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{36-45}{8} = -1.125$

Let X₂ = 4 years = 12 × 4 = 48 months

$Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{48-45}{8} = 0.375$

Step(iii):-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = P(-1.125≤Z≤0.375)

= P(Z≤0.375) - P(Z≤-1.125)

= 0.5 +A(0.375) - (0.5-A(1.125)

= 0.5 + 0.1480 - (0.5 -0.3708)

= 0.1480 + 0.3708

= 0.5188

Final answer:-

The probability that Delta car batteries last between three and four years

P(36≤X≤48) = 0.5188

The percentage of that Delta car batteries last between three and four years

P(3≤X≤4) = 52%

5 0

3 years ago

Write the rate of decay of the function as a percent. y=12(.9)

sleet_krkn [62]

Answer:

18

Step-by-step explanation:

3 0

3 years ago

Which math expression represents the phrase? 8 times the difference of a number and 3

s2008m [1.1K]

Letter A is the correct answer because you can obviously exit out c and d, but yo get a good phrase you might as well have some parentheses to make this work because without it, would be confusing :)

3 0

4 years ago

Read 2 more answers

If you know help me please I’m stuck!

salantis [7]

Answer:

82.4

Step-by-step explanation:

divide 51/13, multiply that result by 21.

7 0

3 years ago