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RSB [31]
3 years ago
13

Simplify: (ax+2)(ax+b)(b)0

Mathematics
2 answers:
Lina20 [59]3 years ago
6 0
0 anything multiplied by Zero is zero
o-na [289]3 years ago
3 0
<span>(ax+2)(ax+b)(b)0 = 0

Any number multiplied by 0 is 0.
</span>
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Which expression is the factored form of −1.5w+7.5 ?
prohojiy [21]

Answer:

c.

Step-by-step explanation:

the most that can be factored out is -1.5,

-1.5 * w = -1.5w

-1.5 * -5 = 7.5

-1.5w + 7.5, so it's

-1.5(w-5)

8 0
3 years ago
3 + 4n + n = 2n + 15.
monitta

Answer:

n = 4

Step-by-step explanation:

3 + 4n + n = 2n +15

3 + 5n = 2n + 15

5n - 2n = 15 - 3

3n = 12

n = 12 / 3

  = <u>4</u>

4 0
4 years ago
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A rectangle was altered by increasing its length by 10 percent and decreasing its width by p percent. If these alterations decre
Roman55 [17]
It is d I hope I helped
4 0
3 years ago
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A plane can travel 480 mph with the wind and 400 miles per hour against the wind find the speed of the wind and the speed of the
dalvyx [7]

Answer:


Step-by-step explanation:

If v = plane velocity and c = air current, then:

v + c = 480

v - c = 400

2v = 880

v = 440

The plane's velocity in still air would be 440 miles per hour.

4 0
3 years ago
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A two-digit locker combination has two nonzero digits and no digit is repeated in any combination.
zzz [600]

Answer:

Answer choice C

Step-by-step explanation:

Similarly to the previous problem, there are two possibilities. In the first possibility, the chance of picking a digit lower than 7 is 6/9 or 2/3, because there are 6 digits below 7 and 9 digits in total. In this scenario, the probability of the second digit being below 7 is 5/8, since one of the digits has already been taken. The probability here is 5/8*6/9=5/12. In the other scenario, the probability of picking a number higher than 7 is 3/9 or 1/3. In this scenario, the probability of picking below 7 for the second digit is 6/8 or 3/4, because one of the digits has not been taken. 3/9*6/8= 1/4. Adding these two together, you get 8/12=2/3, or answer choice C. Hope this helps!

7 0
3 years ago
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