5-(8v+5)= -4(1 + 3v)
2 answers:
You might be interested in
Answer:
Step-by-step explanation:
No. of days of study = 6
Amount of food to use for the 6 days = 72 mm
Given that equal amount of food was used each day, amount used per day =
This would enable us derive a function for the amount of food remaining f(x), which can be expressed as a function of the number of days that have passed, (x).
Thus, we would have:
Let's check if this equation expresses the relation of the function well.
At the end of day 1, if we used, 12mm, we would have 72 - 12 = 60mm of food remaining.
If we replace x in the equation we derived, we would get the same 60mm as the amount of food remaining.
If you try 2, 3, 4, 5 days, you'd get same thing.
At the end of the study, after the 6th day, the food would remain nothing.
Replace 6 for x in the relation function derived, you'd get a value of 0.
Answer:
the probability that their minimum is larger than 5 is 0.2373
Step-by-step explanation:
For calculate the probability we need to make a división between the total ways to selected the 5 numbers and the ways to select the five numbers in which every number is larger than 5.
So the number of possibilities to select 5 numbers from 20 is:
<u>20 </u> * <u> 20 </u>* <u> 20 </u> *<u> 20 </u>* <u> 20 </u>
First number 2nd number 3rd number 4th number 5th number
Taking into account that a number can be chosen more than once, and the order in which you select the numbers matters, for every position we have 20 options so, there are ways to select 5 numbers.
Then the number of possibilities in which their minimum number is larger than 5 is calculate as:
<u>15 </u> * <u> 15 </u>* <u> 15 </u> *<u> 15 </u>* <u> 15 </u>
First number 2nd number 3rd number 4th number 5th number
This time for every option we can choose number from 6 to 20, so we have 15 numbers for every option and the total ways that satisfy the condition are
So the probability P can be calculate as:
Then the probability that their minimum is larger than 5 is 0.2373