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IrinaVladis [17]

3 years ago

11

Prove that

cos 5x/sin17x-sin3x=-sin2x/cos10x" alt="cos 9x-cos 5x/sin17x-sin3x=-sin2x/cos10x" align="absmiddle" class="latex-formula">

1 answer:

maria [59]3 years ago

8 0

Cos9x - cos5x = -2sin2x.sin7x
sin17x - sin3x = 2sin7x.cos10x
so f(x) = $\frac{-2sin2x.sin7x}{2sin7x.cos10x}$ = $\frac{-sin2x}{cos10x}$

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