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4 years ago

7

Circle theorem - easy work

1 answer:

makvit [3.9K]4 years ago

8 0

Angle in a semi circle is 90°
<a = 180-90-<b = 90-28 = 62°

opposite angles of a cyclic quadrilateral sums up to 180°
<b + <a = 180
<b = 180-62
<b = 118°

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Answer:

$E\ n\ F = \{1, 5, 6,7\}$

$F\ n\ G =\{9\}$

$F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}$

$P(F\ U\ G) = \frac{3}{4}$

Step-by-step explanation:

Given

$S = \{1,2,3,4, 5,6,7,8, 9, 10, 11, 12\}$

$E = \{1,2, 3, 4, 5, 6,7\}$

$F =\{1,5,6, 7, 8,9\}$

$G = \{9,10, 11, 12\}$

$H = \{2, 3, 4\}$

Solving (5): E and F

Sets of E and F = E n F

$E\ n\ F = \{1,2, 3, 4, 5, 6,7\}\ n\ \{1,5,6, 7, 8,9\}$

List out common elements

$E\ n\ F = \{1, 5, 6,7\}$

<em>They are not mutually exclusive because </em> $n(E\ n\ F) \neq 0$ <em />

Solving (6): F and G

Sets of F and G = F n G

$F\ n\ G =\{1,5,6, 7, 8,9\}\ n\ \{9,10, 11, 12\}$

List out common elements

$F\ n\ G =\{9\}$

<em>They are not mutually exclusive because </em> $n(F\ n\ G) \neq 0$ <em />

Solving (7): F or G and P(F or G)

Sets of F or G = F U G

$F\ U\ G =\{1,5,6, 7, 8,9\}\ U\ \{9,10, 11, 12\}$

List all elements without repetition

$F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}$

Solving P(F U G)

$P(F\ U\ G) = \frac{n(F\ U\ G)}{n(S)}$

$n(F\ U\ G) = 9$

$n(S) = 12$

Hence;

$P(F\ U\ G) = \frac{9}{12}$

Divide by 3

$P(F\ U\ G) = \frac{3}{4}$

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Answer: it think it’s the third one

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