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Tasya [4]
3 years ago
6

A survey of 260 families show that 99 had dog 76 had cat 34 had dog and cat 98 had neither a cat nor a dog nor a parakeet 8 had

a cat a dog and a parakeet

Mathematics
1 answer:
Archy [21]3 years ago
5 0

Answer:

<u>Option D. 21</u>

Step-by-step explanation:

The question is as shown in the attached figure 1

The Venn diagram representing the problem is the attached figure 2

D ⇒ Dog , C⇒ Cat  and P ⇒ parakeet

Let the The families had parakeet only = X

A survey of 260 families show that:

99 had dog

76 had cat

34 had dog and cat

98 had neither a cat nor a dog nor a parakeet

8 had a cat a dog and a parakeet

So,

The families had a dog and a cat only = 34 - 8 = 26

The families had a dog only = 99 - (26 + 8 ) = 65

The families had a cat only = 76 - (26 + 8) = 42

∴ X = 260 - ( 98 + 8 + 26 + 65 + 42 ) = 260 - 239 = 21

So, The families had a parakeet only = 21

<u>The answer is option D</u>

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