Answer:
We should limit the use of carbon dioxide,such as making more electric cars,and limit greenhouse gasses.
Os itens usados para o comércio nas colônias do sul das Colônias incluíam tabaco, algodão, arroz, índigo (corante), madeira, peles, produtos agrícolas, muitos dos quais foram produzidos nas plantações de escravos.
Answer:
Line OX = 7.09
Explanation:
The question is incomplete. Find attached the complete question.
SOLUTION
Given:
Line OL is perpendicular to DX
Line DX = 13
Line PO = the hypotenuse of the larger triangle
Line PO = 10
Line BO = hypotenuse of smaller triangle
Line BO = 12
To find length of line OX, we would apply rule of similar and congruent triangles.
∆DPO = ∆XBO
<POD = <BOX
Line DP is parallel to line XB
Since length of side DX = 13
Side DX = side DO + side OX
Let side DO = x
Side OX = 13-x
(Adj of ∆DPO)/(Adj of ∆XBO) = hyp of ∆DPO/hyp of ∆XBO
DO/OX = PO/BO
x/ (13-x) = 10/12
12x = 10(13-x)
12x = 130-10x
12x +10x = 130
22x = 130
x = 130/22 = 65/11
x is approximately = 5.91
Therefore line OX = 13 - 5.91
Line OX = 7.09
He got it at the cave Hira
Answer:
The age of the rock = 2800.6 million years = 2.8 billion years.
A simple method of analysis similar to Carbon dating is used to obtain the required age of the rock. Radioactive substances decay according to first order reaction kinetics. So, plugging all the required parameters into the general equation for amount of substance left in a first order decay gives us the age of the rock.
Explanation:
Half life of Uranium-235 = 700 million years (from literature)
The decay of radioactive substances follow first order reaction kinetics.
The general equation is given as
A(t) = A₀ e⁻ᵏᵗ
A(t) = Amount of radioactive substance left after a particular time = 6.25%
A₀ = initial amount of radioactive substance = 100%
t = time that has passed since the beginning = age of the rock = ?
k = decay constant
The decay constant is related to the half life (T) through the relation,
k = (In 2)/T
k = (0.693/700) = 0.00099 /million years
A(t) = A₀ e⁻ᵏᵗ
6.25 = 100 e⁻ᵏᵗ
0.0625 = e⁻ᵏᵗ
In e⁻ᵏᵗ = In 0.0625 = -2.7726
-kt = - 2.7726
t = (2.7726/0.00099) = 2800.6 million years
t = 2.8 billion years.
Hope this Helps!!!