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labwork [276]
3 years ago
7

50 points - geometry - pictures attached

Mathematics
2 answers:
Volgvan3 years ago
7 0

Answer:

Step-by-step explanation:

PQ ≅ PR                                              Given

Draw median PM                                Two points determine a line

Point M is the midpoint of QR          Definition of median

QM ≅ RM                                             Definition of midpoint

PM ≅ PM                           Reflexive property of congruence

ΔPQM ≅ ΔPRM            SSS Congruence postulate

∠Q ≅    ∠R                  CPCTC

Yuki888 [10]3 years ago
4 0

Answer:

The answer to your question is below

Step-by-step explanation:

PQ ≅ PR                                              Given

Draw median PM                                Two points determine a line

Point M is the midpoint of QR          Definition of median

QM ≅ RM                                             Definition of midpoint

PM ≅ PM                                              Reflexive property of congruence

ΔPQM ≅ ΔPRM                                    SSS Congruence postulate

∠Q ≅    ∠R                                          CPCTC

"I hope it helps you"

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Jobisdone [24]

9514 1404 393

Answer:

  if and only if the rectangle is a square

Step-by-step explanation:

The angle bisectors of a rectangle will meet at a single point if, and only if, the rectangle is a square.

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The incircle must be tangent to all sides of the polygon. That cannot be the case unless the rectangle has its length equal to its width. That is, it must be a square.

5 0
2 years ago
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3 years ago
Write an<br> i explicit formula for an, the nth term of the sequence 200, 40, 8, ....
Ugo [173]

Answer:

T_n = 200 * (\frac{1}{5})^{n-1

Step-by-step explanation:

Given

Sequence: 200,40,8

Required

The nth term

The given sequence is a geometric sequence.

So, first we identify the first term

a = 200

Calculate common ration

r = \frac{40}{200} or r = \frac{8}{40}

r = \frac{1}{5}

So, the nth term is:

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5 0
2 years ago
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horsena [70]
-32 ^{- \frac{3}{5} }

\frac{1}{-32}^{ \frac{3}{5} }

= \sqrt[5]{ (\frac{1}{-32}) ^{3}  }

=- \frac{1}{8}

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4 0
2 years ago
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