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Andreas93 [3]
3 years ago
8

Consider the following scenario: Let P(C) = 0.4. Let P(D) = 0.5. Let P(C|D) = 0.6. a. Find P(C AND D). b. Are C and D mutually e

xclusive? Why or why not? c. Are C and D independent events? Why or why not? d. Find P(C OR D). e. Find P(D|C).
Mathematics
1 answer:
Nataly_w [17]3 years ago
3 0

a. By definition of conditional probability,

P(C | D) = P(C and D) / P(D)  ==>  P(C and D) = 0.3

b. C and D are mutually exclusive if P(C and D) = 0, but this is clearly not the case, so no.

c. C and D are independent if P(C and D) = P(C) P(D). But P(C) P(D) = 0.2 ≠ 0.3, so no.

d. Using the inclusion/exclusion principle, we have

P(C or D) = P(C) + P(D) - P(C and D)  ==>  P(C or D) = 0.6

e. Using the definition of conditional probability again, we have

P(D | C) = P(C and D) / P(C)  ==>  P(D | C) = 0.75

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Answer: the cost of one cherry pie is $18 and the cost of one pumpkin pie is $20

Step-by-step explanation:

Let x represent the cost of one cherry pie.

Let y represent the cost of one pumpkin pie.

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Kali sold 7 cherry pies and 8 pumpkins pies for a total of $286. This means that

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Multiplying equation 1 by 7 and equation 2 by 2, it becomes

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2x + 4 × 20 = 116

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2x = 116 - 80 = 36

x = 36/2 = 18

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