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Lynna [10]
3 years ago
12

Find the value of x.

Mathematics
2 answers:
alexira [117]3 years ago
7 0
X+x+4+3x-9=90
5x-5=90
+5 +5
5x=95
5x/5=95/5
x=19
AURORKA [14]3 years ago
7 0
Okay the value of x is 19
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Find (f/g) (x) and state the domain restriction. f (x) = 6x - 3 and g(x) = 12x^2 - 6x
Rufina [12.5K]

9514 1404 393

Answer:

  (f/g)(x) = 1/(2x)

  x ≠ 1/2

Step-by-step explanation:

  (f/g)(x)=\dfrac{f(x)}{g(x)}=\dfrac{6x-3}{12x^2-6x}=\dfrac{6x-3}{2x(6x-3)}\\\\\boxed{(f/g)(x)=\dfrac{1}{2x}}\quad x\ne\dfrac{1}{2}

The domain restriction x ≠ 1/2 comes from the requirement to prevent the denominator factor 6x-3 from being zero.

8 0
3 years ago
A study suggested that childrenbetween the ages of 6 and 11 in the US have anaverage weightof 74 lbs. with a standard deviation
Doss [256]

Answer:

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A study suggested that children between the ages of 6 and 11 in the US have an average weightof 74 lbs, with a standard deviation of 2.7 lbs.

This means that \mu = 74, \sigma = 2.7

What proportion of childrenin this age range between 70 lbs and 85 lbs.

This is the pvalue of Z when X = 85 subtracted by the pvalue of Z when X = 70. So

X = 85

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 74}{2.7}

Z = 4.07

Z = 4.07 has a pvalue of 1

X = 70

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 74}{2.7}

Z = -1.48

Z = -1.48 has a pvalue of 0.0694

1 - 0.0694 = 0.9306

The proportion of children in this age range between 70 lbs and 85 lbs is of 0.9306.

7 0
3 years ago
Graham paid $87.45 for a pair of jeans. This amount included a tax of 40%. What was the cost of the jeans before tax?
kiruha [24]

The final price is the cost plus the tax.

Since we know the tax and a percent, we can write this as

T = C(1+r)

T = what Graham paid = $87.45

C = cost before tax

r = tax rate expressed as a decimal = .40

Plugging in what we know

87.45 = C (1+.4)

87.45 = C(1.4)

Divide both sides by 1.4

C = $62.46

5 0
3 years ago
Factor the equation.
Kryger [21]
Hi!

The fully factored form of this equation is (3x+2)²
5 0
3 years ago
Alex needs 36 boxes in the carton above.
olganol [36]

Answer:

1 stack of 36

Step-by-step explanation:

First find how much one carton can hold

length is 45

width is 20

height is 40

40 * 20 * 45 = 36,000

Then find how much volume each box has

length is 20

width is 10

height is 5

5 * 10 * 20 = 1000

so each box is 1000 volume

1 stack of 36 is good

7 0
3 years ago
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