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AlexFokin [52]
3 years ago
6

Kremena's bank account earns 4.5% simple interest per year. How much must she deposit in the account today if she wants it to be

worth $1,250 in 3 years? Round your answer to the nearest dollar.
Mathematics
2 answers:
Sever21 [200]3 years ago
7 0

Answer: $1101 must be deposited into the account.

Step-by-step explanation:

Let x represent the amount that must be deposited.

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents the interest after T years.

P represents the principal or initial amount deposited.

T represents the amount of time for which the money is left in the account in years.

R represents the interest rate.

From the information given,

P = $x

T = 3 years

R = 4.5%

I = 1250 - x

Therefore,

1250 - x = (x × 4.5 × 3)/100

1250 - x = 0.135x

x + 0.135x = 1250

1.135x = 1250

x = 1250/1.135

x = 1101 to the nearest dollar

oksian1 [2.3K]3 years ago
6 0

Answer:

1095$ should be invested today .

Step-by-step explanation:

The formula of present value will be applied here :

Present Value= Future Value/(1+ interest rate)^Years

Present Value = 1250/(1.045)^3

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Please help #3 will mark brainliest
Darina [25.2K]

Answer:

im preety sure its c

Step-by-step explanation:

8 0
3 years ago
Which statement is true ?
8090 [49]

Answer:

f(x)=4x^2

f(2)=4(2)^2

f(2)=4(4)

f(2)=16

2. g(x)=4*2^x

g(2)=4*2^2

g(2)=4*4

g(2)=16

f(2)=g(2)

Both is equal to 16

I hope this help you :)

Step-by-step explanation:

8 0
3 years ago
Which of the following shows the graph of y = 4x 3? on a coordinate plane, an exponential function starts at y = 3 in quadrant 2
ZanzabumX [31]

The graph of the linear equation y = 4x + 3 can be seen at the end of the answer.

<h3>How to find the graph of the given line?</h3>

Here we have the linear equation:

y = 4x + 3.

To graph it, we need to find two points that belong to the line, to do that, we evaluate in two different values of x. I will use x = 0 and x = 2.

When x = 0.

y = 4*0 + 3 = 3

So we have the point (0, 3).

When x = 2:

y = 4*2 + 3 = 8 + 3 = 11

So we have the point (2, 11)

Now we just need to graph these two points and connect them with a line. The graph of the linear equation is the one you can see below.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ5

5 0
2 years ago
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
3 years ago
Can you please help?
gogolik [260]

Answer:

sry i cant help you bcoz i havent read this type of exercise yet

8 0
2 years ago
Read 2 more answers
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