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olga_2 [115]
3 years ago
13

Evaluate -7 - (-8) + (-3) + 6 - 2

Mathematics
2 answers:
Andru [333]3 years ago
6 0

Answer:

2

Step-by-step explanation:

tigry1 [53]3 years ago
6 0
Answer is 2

-7+8-3+6-2

-12+14

2

Brainliest?
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Last week DeShawn ran 31 kilometers less than Amanda. DeShawn ran 13 kilometers. How many kilometers did Amanda run?
schepotkina [342]
31+13=44 miles ran by amanda
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- Olivia skates twice as far as Stephanie. This sum of their distances is 96 miles per month. How many
kotegsom [21]

Answer:

B.64 miles

Step-by-step explanation:

Let Oliver's be x

Let Stephanie's be y

x = 2y -  -  - (a) \\ x + y = 96 -  -  - (b)

substitute for x in (b):

2y + y = 96 \\ 3y = 96 \\ y = 32

find x in (a):

x = (2 \times 32) \\ x = 64

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3 years ago
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Neil has 3 partially full cans of white paint. They cantain 1/3 gallon, 1/5 gallon, and 1/2 gallon of paint. About how much pain
Marianna [84]

Answer:

1  1/30 gallons, or 31/30 gallons of paint

Step-by-step explanation:

Before these fractions can be added together they have to have a common denominator.  The Least Common Multiple of 2, 3, and 5 is 30, so

1/3 = 10/30   1/5 = 6/30   1/2 = 15/30

10/30 + 6/30 + 15/30 = 31/30, or 1  1/30

6 0
3 years ago
A grocer wants to make a 10-pound mixture of peanuts and cashews that he can sell for $4.75 per pound. If peanuts cost $4.00 per
ValentinkaMS [17]

Answer:

3lbs

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8 0
3 years ago
(a) Find a vector parallel to the line of intersection of the planes −4x+2y−z=1 and 3x−2y+2z=1.
valentinak56 [21]

Find the intersection of the two planes. Do this by solving for <em>z</em> in terms of <em>x</em> and <em>y </em>; then solve for <em>y</em> in terms of <em>x</em> ; then again for <em>z</em> but only in terms of <em>x</em>.

-4<em>x</em> + 2<em>y</em> - <em>z</em> = 1   ==>   <em>z</em> = -4<em>x</em> + 2<em>y</em> - 1

3<em>x</em> - 2<em>y</em> + 2<em>z</em> = 1   ==>   <em>z</em> = (1 - 3<em>x</em> + 2<em>y</em>)/2

==>   -4<em>x</em> + 2<em>y</em> - 1 = (1 - 3<em>x</em> + 2<em>y</em>)/2

==>   -8<em>x</em> + 4<em>y</em> - 2 = 1 - 3<em>x</em> + 2<em>y</em>

==>   -5<em>x</em> + 2<em>y</em> = 3

==>   <em>y</em> = (3 + 5<em>x</em>)/2

==>   <em>z</em> = -4<em>x</em> + 2 (3 + 5<em>x</em>)/2 - 1 = <em>x</em> + 2

So if we take <em>x</em> = <em>t</em>, the line of intersection is parameterized by

<em>r</em><em>(t)</em> = ⟨<em>t</em>, (3 + 5<em>t</em> )/2, 2 + <em>t</em>⟩

Just to not have to work with fractions, scale this by a factor of 2, so that

<em>r</em><em>(t)</em> = ⟨2<em>t</em>, 3 + 5<em>t</em>, 4 + 2<em>t</em>⟩

(a) The tangent vector to <em>r</em><em>(t)</em> is parallel to this line, so you can use

<em>v</em> = d<em>r</em>/d<em>t</em> = d/d<em>t</em> ⟨2<em>t</em>, 3 + 5<em>t</em>, 4 + 2<em>t</em>⟩ = ⟨2, 5, 2⟩

or any scalar multiple of this.

(b) (-1, -1, 1) indeed lies in both planes. Plug in <em>x</em> = -1, <em>y</em> = 1, and <em>z</em> = 1 to both plane equations to see this for yourself. We already found the parameterization for the intersection,

<em>r</em><em>(t)</em> = ⟨2<em>t</em>, 3 + 5<em>t</em>, 4 + 2<em>t</em>⟩

3 0
3 years ago
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