Answer:
6.28 + 24 + 3 + 2 = 35.28 sq. units
Step-by-step explanation:
The screenshot is how I split it. (A semicircle with a radius of 2, a trapezoid (base a: 5, base b: 7, height 4), and two triangles (b1: 3, h1: 2; b2: 4, h2: 1)
To find the area of a semicircle, use the formula πr²/2. I'll use 3.14 for pi.
3.14(2²)/2
<em>Square 2 to get 4.</em>
3.14(4)/2
<em>Multiply 3.14 by 4 to get 12.56.</em>
12.56/2
<em>Divide 12.56 by 2 to get 6.28</em>
The semicircle is 6.28 units².
To find the area of a trapezoid, use the formula (a+b)h/2.
(5 + 7) * 4/2
<em>Add 5 and 7 to get 12.</em>
(12 * 4)/2
<em>Multiply 12 by 4 to get 48.</em>
48/2
<em>Divide 48 by 2 to get 24.</em>
The trapezoid is 24 units².
For the triangles, simply use this: bh/2
3 * 2 / 2
<em>The 2's cancel out, so you're simply left with </em><em>the first triangle being 3 units².</em>
4 * 1 / 2
<em>This really just becomes 4/2 as 4 * 1 is just 4.</em>
4/2
<em>Divide 4 by 2 to get 2.</em>
The second triangle is 2 units².
Now that we know the areas of the four figures, add them together.
6.28 + 24 + 3 + 2
6.28 + 27 + 2
6.28 + 29
The area of the figure is 35.28 units².