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natka813 [3]
3 years ago
5

Refer to the test i need help on all of them please i need it quick i will mark brainliest!!!

Mathematics
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

1) D

2) B

3) A

4) C

5) A

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Jeff typed a 5-page term paper with 600 words per page. He typed an average of 40 words per minute. If he started typing at 8:15
Leno4ka [110]

Answer:

If Jeff is types 5 pages at 600 words per page, then he types 3,000 words (5 x 600).

So, if Jeff started typing at 8:15 am, he'd finish at 9:30 am.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
How many ml of a 20% acid mixture and a 80% acid mixture should be mixed to get 120ml of a 35% acid mixture?
shutvik [7]

Answer:

Volume of Mixture A =90 ml

Volume of Mixture B =30 ml

Step-by-step explanation:

Let say, Mixture A + Mixture B = Mixture C

Volume of Mixture A is x

Volume of Mixture B is y

So, Volume of Mixture C is x+y = 120 ml

Now, Acid contain in Mixture A is 20% =0.2x

Acid contain in Mixture B is 80% =0.8y

Also, Acid contain in Mixture C is 35% =(0.35)(x+y) = 0.35×120=42

Now, we know that,

Acid contain of Mixture A + Acid contain of Mixture B=Acid contain of Mixture C

∴ 0.2x+0.8y=42

∴ 2x+8y=420

We get two linear equations

2x+8y=420 and x+y = 120

Solving above equation...

∴ x=120-y

Replacing x value in 2x+8y=420

∴ 2(120-y)+8y=420

∴ 240-2y+8y=420

∴ 6y=180

∴ y=30

Replacing y value in any equation

∴ x=120-y=120-30=90

∴ x=90

Thus,

Volume of Mixture A is x=90 ml

Volume of Mixture B is y=30 ml

3 0
4 years ago
If you are doing area in mathematics and the base is 16 and the height is 5 but there are 4 sides, don't u need to multiply 16x5
Murrr4er [49]
No, you would only need to multiply 16 by 5 once
4 0
3 years ago
which will increase the volume of a square pyramid more doubling the length of each side of tripling the height (hint test it wi
Furkat [3]
Im pretty sure it would be doubling the length of each side
8 0
3 years ago
Read 2 more answers
A 46 gram sample of a substance that is used to sterilize surgical instruments has a k-value of 0.1374. Find the substance's hal
mars1129 [50]

Answer:

  t=5.0days

Step-by-step explanation:

Using the formula for the exponential decay that is N=N_{0}e^{-kt}, we have N=\frac{1}{2}{\times}46=23, N_{0}=46 and k=0.1374.

Thus, N=N_{0}e^{-kt} becomes

23=46{\times}e^{-0.1374t}

\frac{23}{46}=e^{-0.1374t}

\frac{1}{2}=e^{-0.1374t}

Taking log on both sides, we get

ln(\frac{1}{2})={-0.1374t}

t=\frac{ln\frac{1}{2}}{-0.1}

t=\frac{-0.6931}{-0.1374}

t=5.0days

4 0
3 years ago
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