Answer:
3p^3 + qp^2 - pq^2 + 3q^3
Step-by-step explanation:
(p²-pq + q²) ( 3p+ 3q)
3p^3 + 3qp^2 - 3qp^2 - 3pq^2 + 3pq^2 + 3q^3
3p^3 + qp^2 - pq^2 + 3q^3
F(x) = (1/2)x + 4
Plug y in for f(x).
y = (1/2)x + 4
Swap x and y.
x = (1/2)y + 4
Solve the equation for y =.
Subtract 4 from both sides.
x - 4 = (1/2)y
Multiply each term 2.
2x - 8 = y
Plug f^-1(x) in for y.
f^-1(x) = 2x - 8
f^-1(4) = 2(4) - 8
f^-1(4) = 0
What’s the cost before the tip? We need to know that before calculating the cost with the tip.
The answer is: - 6 .
_____________________________________________
Evaluate the value INSIDE the "bars".
b - a = -2 - 4 = -6 . The absolute value of the value inside inside the bars is the "positive" number of that value. The value is negative 6; so, the absolute value, or "magnitude", of "-6", is "6"; Then, then "-" (6) = -6. So the answer is: -6 .
___________________________________________________