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Airida [17]
3 years ago
13

How do you solve linear systems

Mathematics
1 answer:
cluponka [151]3 years ago
8 0

Answer:

Using various of methods. It depends of your solving it on a graph, table, etc.

Step-by-step explanation:

You can put it in slope-intercept form (My fav), standard form, point-slope form, you can find the rate change (Y is over X), etc.

You might be interested in
the value of x=4 is the solution to all following equation except witch? 2x+7=15 x+5=3x-3 3(x+1)=x+11 or x+12=5x-2
garri49 [273]
Except x+12=5x-2 
because:
4+12= 5*4-2
16=20-2
16=18 -- which is not true 

7 0
3 years ago
Evaluate the limit 8n^2+5n+2/3+2n
Vlada [557]

Answer:

8n^2+7n+2/3

Step-by-step explanation:

combine like terms

5n+2n=7n

7 0
3 years ago
Read 2 more answers
HELP! PLEASE! I really need help with this question!
LekaFEV [45]

Answer:

They are at the same height at 1.13 seconds.

Step-by-step explanation:

Remark

The rockets are at the same height when  f(x) = g(x) [see below] are the same. So you can equate them.

Givens

f(x) = - 16x^2 + 74x + 9

g(x) = -16x^2 + 82x              I have changed this so you don't have 2 f(x)s

Solution

  • f(x) = g(x)
  • -16x^2 + 74x + 9 = -16x^2 + 82x                        Add:  16x^2 to both sides
  • -16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x   Combine terms
  • 74x + 9 = 82x                                                     Subtract 74x from both sides
  • 74x - 74x + 9 = 82x - 74x                                  Combine
  • 9 = 8x                                                                 Divide by 8
  • 9/8 = 8x/8
  • x = 1 1/8                                                              Convert to decimal
  • x = 1.125
  • x = 1.13  [rounded]


6 0
3 years ago
Two questions in one.
s2008m [1.1K]
Question 1: 4.375/10 of an hour (or 26.25 minutes)
4 0
3 years ago
Solved i need the answer ASAP
makkiz [27]

Answer:

V = - 3

Step-by-step explanation:

- 1 =  \frac{1}{3} v \\  \\  - 1 \times 3 = v \\  \\ v =  - 3

Your answer is absolutely correct.

8 0
3 years ago
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