Answer:
Explanation:
The following code is written in Python. It asks the user to enter the current balance and the annual interest rate. It then calculates the monthly interest rate and uses that to detect the interest that will be earned for the next month. Finally, printing that to the screen. A test output can be seen in the attached picture below.
balance = int(input("Enter current Balance: "))
interest = int(input("Enter current annual interest %: "))
interest = (interest / 12) / 100
next_month_interest = balance * interest
print('$ ' + str(next_month_interest))
Answer:
An operating system can be categorized according to both the given options. Thus answer is option C
Explanation:
An operating system should support multiple logins. Because the login plays a major role and that is the need and mainly in the organization where one system will be shared by multiple users. Also, Operating system should perform multi-tasking. This efficiency is required so that the user completes the work very faster and he need not wait to go for the next task.
For example an operating system handles user’s task, background tasks, keep track of the status of the devices, allots output device to the requested user and so on.
Answer:
The program in C++ is as follows:
#include <iostream>
#include <vector>
using namespace std;
int main(){
int n;
cout<<"Elements: ";
cin>>n;
vector <int>num;
int input;
for (int i = 1; i <= n; i++){ cin>>input; num.push_back(input); }
int large, seclarge;
large = num.at(0); seclarge = num.at(1);
if(num.at(0)<num.at(1)){ large = num.at(1); seclarge = num.at(0); }
for (int i = 2; i< n ; i ++) {
if (num.at(i) > large) {
seclarge = large;;
large = num.at(i);
}
else if (num.at(i) > seclarge && num.at(i) != large) {
seclarge = num.at(i);
}
}
cout<<"Second Largest: "<<seclarge<<endl;
int small, secsmall;
small = num.at(1); secsmall = num.at(0);
if(num.at(0)<num.at(1)){ small = num.at(0); secsmall = num.at(1); }
for(int i=0; i<n; i++) {
if(small>num.at(i)) {
secsmall = small;
small = num.at(i);
}
else if(num.at(i) < secsmall){
secsmall = num.at(i);
}
}
cout<<"Second Smallest: "<<secsmall;
return 0;
}
Explanation:
See attachment for explanation
