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3 years ago

Is the following shape a right triangle? How do you know?

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

Answer:

D. Yes, two sides are perpendicular, and the side lengths fit the

Pythagorean theorem.

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A = 10, b = 24, c = _____

Arlecino [84]

Answer:

c=26

Step-by-step explanation:

By using pythagoram thoerem

c^2=a^2+b^2

c^2=(10)^2+(24)^2

c^2=100+576

c^2=676

c=sqrt(676)

c=26

3 0

3 years ago

Which of the following scenarios demonstrates sampling bias? (A) To estimate the ethnic background distribution of residents of

ankoles [38]

Answer:

Option C.

Step-by-step explanation:

Sampling bias is a problem during the initial data gathering step of a survey.

When the first step is wrong, then the survey cannot produce non biased results.

The problem occurs when the design of the study is wrong the data collection procedure is wrong.

So, here answer seems C, because the starting point is not selected at random in this survey.

(C) Jean wants to estimate the mean amount of money spent on clothes per week by mall shoppers. She collects data from every 10th person entering a clothing store at the mall.

6 0

3 years ago

Find log1/4 rounded to the nearest hundredth.

erastovalidia [21]

Answer:

-log_4

Step-by-step explanation:

4 0

2 years ago

Select the proper order from least to greatest for 1/2, 5/6, 2/7, 4/2?

mamaluj [8]

The least is 2/7 then 1/2 then 5/6 and the greatest is 4/2

8 0

3 years ago

Read 2 more answers

Find the limit if it exists lim x→0 sqrtx+7-sqrt7 over x

Triss [41]

Answer:

$\frac{1}{ 2\sqrt{7} }$

Step-by-step explanation:

$\lim_{x\to 0} \frac{ \sqrt{x + 7} - \sqrt{7} }{x} \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} - \sqrt{7}) }{x} \times \frac{( \sqrt{x + 7} + \sqrt{7}) }{( \sqrt{x + 7} + \sqrt{7}) } \\ \\ = \lim_{x\to 0} \frac{( \sqrt{x + 7} )^{2} - (\sqrt{7})^{2} }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{( {x + 7} - {7}) }{x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {\cancel x}}{\cancel x( \sqrt{x + 7} + \sqrt{7})} \\ \\ = \lim_{x\to 0} \frac{ {1}}{\sqrt{x + 7} + \sqrt{7}} \\ \\ = \frac{1}{ \sqrt{0 + 7} + \sqrt{7} } \\ \\ = \frac{1}{ \sqrt{7} + \sqrt{7} } \\ \\ = \frac{1}{ 2\sqrt{7} }$

6 0

3 years ago