Hope this helps <span>1) </span><span>Equations with negative values for a</span><span> produce graphs that open down and equations with a positive values for a</span> produce graphs that open up.
<span>2)<span> </span></span><span>As the absolute value of a gets larger our graphs become more narrow (they shoot towards positive or negative infinity faster). This is more interesting than it might appear. If you consider the second derivative of any quadratic it will be the a</span><span> value. The second derivative represents acceleration, so the larger the a value the faster the increase of velocity and accordingly a quicker progression towards positive or negative infinity. Check this out in graphing calculator, press play to vary the value of a from -20 to 20. Notice that when the value of a approaches zero, the approximates a line, and of course when a is 0 we have the line y</span><span> = 2x</span><span> – 1.</span>
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The number of times is n = 20
The probability of getting three or more heads in a row is 
The probability of getting three or more heads in a row or three or more tails in a row is 
Generally given that it is a fair coin , then 
Here P(T) is probability of getting three or more tails in a row
Generally the probability of getting three or more heads in a row and three or more tails in a row is mathematically represented as
=> 
=>
less than because when it turns negative it reverses how it would normally be. so 6 is greater than 5 but -6 is less than -5
Answer:
n = 5/2
Step-by-step explanation:
(2n + 4) + 6 = -9 + 4(2n + 1)
2n + 4 + 6 = -9 + 8n + 4
2n + 10 = 8n - 5
15 = 6n
n = 5/2
Hope this helps!
Add (11/2)^2 to both sides
x^2 + 11x + (11/2)^2 = 3 + (11/2)^2
x^2 + 11x + (11/2)^2 = 133/4
(x + 11/2)^2 = 133/4
x + 11/2 = sqrt of (133/4)
Solutions are
x = (sqrt of (133) - 11))/2
x = (-sqrt of (133) -11))/2
