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sattari [20]
3 years ago
9

Find the product of 7x and 13x^2-8

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0
7x (13x^2 - 8) = 91x^3 - 56x
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PLEASE HELP ME PLEASE
Ray Of Light [21]

Answer:

The computer loses 50%, percent of its value each year.

Step-by-step explanation:

See the graph attached.

A computer is sold for a certain price and then its value changes exponentially over time.

It is clear from the graph that at t = 0, the price was $500, then at t = 1 year, the price was $250 and at t = 2 years, the price was $125 and at t= 3 years, the price was $62.5 and so on.

Therefore, the computer loses 50%, percent of its value each year. (Answer)

5 0
3 years ago
Hence solve the equation x^3+x^2-6x=0<br>​
Aneli [31]

<em>Answer:</em>

<em />

<em>x³ + x² - 6x = 0</em>

<em>x(x² + x - 6) = 0</em>

<em>x(x² + 3x - 2x - 6) = 0</em>

<em>x[x(x + 3) - 2(x + 3)] = 0</em>

<em>x(x - 2)(x + 3) = 0</em>

<em>x₁ = 0</em>

<em>x - 2 = 0 => x₂ = 2</em>

<em>x + 3 = 0 => x₃ = - 3</em>

4 0
3 years ago
Read 2 more answers
X + (-9) + 9 = 8 solve the equation using mental math
Studentka2010 [4]

Answer:

X=8 simplify equation

Step-by-step explanation:

-9+9=0

8 0
3 years ago
How to find the circumference of a cirlcle
Otrada [13]
\sf{Circumference = 2\times\pi\times~r}

Where r is the radius of the circle.
7 0
3 years ago
There are two consecutive positive even integers such that the square of the first is 364 more than five times the second. What
xxMikexx [17]

Answer:

Step-by-step explanation:

There are two consecutive positive even integers such that the square of the first is 364 more than five times a second. What are the two numbers?

Two consecutive year positive integers are represented by

x and x + 1

First integer = x

Second integer = y

There are two consecutive positive even integers such that the square of the first is 364 more than five times a second.

This is represented mathematically as:

x² = 364 + 5(x + 1)

x² = 364 + 5x + 5

x² -5x -5 - 364

x² - 5x - 369

6 0
3 years ago
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