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sattari [20]
3 years ago
9

Find the product of 7x and 13x^2-8

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0
7x (13x^2 - 8) = 91x^3 - 56x
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Please help with math
kykrilka [37]

Answer:

2nd option, x > 1.10

Step-by-step explanation:

7e^{2x}-5 > 58

Add 5 to both sides,

7e^{2x}-5+5 > 58 +5\\7e^{2x} > 63

Divided both sides by 7,

\frac{7e^{2x}}{7} > \frac{63}{7}

e^{2x} > 9

Apply Exponent Rule,

2x > 2ln(3)

\frac{2x}{2} > \frac{2ln(3)}{2}

x > ln(3) or x > 1.09861

Learn more about logarithms here: brainly.com/question/12049968

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You deposit $5000 in a bank account that pays 3.5% annual
miskamm [114]

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Its A i just took the test

Step-by-step explanation:

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3 years ago
What is the slope of a line perpendicular to the line whose equation is x + 3y = -12
emmainna [20.7K]

Answer:

5

Step-by-step explanation:

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8 0
2 years ago
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ivanzaharov [21]

Answer:

It is C

Step-by-step explanation:

5 0
3 years ago
A stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer. If the top laye
Svetlanka [38]

Answer:  The total number of logs in the pile is 6.

Step-by-step explanation:  Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two​ logs.

We are to find the total number of logs in the pile.

Let n represents the total number of logs in the pile.

Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with

first term, a = 32  and  common difference, d = -6.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is

a_n=a+(n-10)d.

Since there are n logs in the pile, so we get

a+(n-1)d=2\\\\\Rightarrow 32+(n-1)(-6)=2\\\\\Rightarrow 32-6n+6=2\\\\\Rightarrow 6n=36\\\\\Rightarrow n=6.

Thus, the total number of logs in the pile is 6.

6 0
2 years ago
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