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sattari [20]
3 years ago
9

Find the product of 7x and 13x^2-8

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0
7x (13x^2 - 8) = 91x^3 - 56x
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I need help) (only the answer) *links and wrong answers will be reorted*
scZoUnD [109]

Answer:

Volume of cuboid = 300 in³

Surface area of cuboid = 280 in²

Step-by-step explanation:

Given:

Length = 10 in

Width = 5 in

Height = 6 in

Find:

Volume of cuboid

Surface area of cuboid

Computation:

Volume of cuboid = [L][B][H]

Volume of cuboid = [10][5][6]

Volume of cuboid = 300 in³

Surface area of cuboid = 2[lb][bh][hl]

Surface area of cuboid = 2[(10)(5) + (5)(6) + (6)(10)]

Surface area of cuboid = 2[50 + 30 + 60]

Surface area of cuboid = 2[140]

Surface area of cuboid = 280 in²

4 0
2 years ago
Find the values of k so that each remainder is three. <br> 10. (x^2+ 5x + 7) = (x + k)
Goryan [66]

Answer:

k=1\text{ or } k=4

Step-by-step explanation:

We can use the Polynomial Remainder Theorem. It states that if we divide a polynomial P(x) by a <em>binomial</em> in the form (x - a), then our remainder will be P(a).

We are dividing:

(x^2+5x+7)\div(x+k)

So, a polynomial by a binomial factor.

Our factor is (x + k) or (x - (-k)). Using the form (x - a), our a = -k.

We want our remainder to be 3. So, P(a)=P(-k)=3.

Therefore:

(-k)^2+5(-k)+7=3

Simplify:

k^2-5k+7=3

Solve for <em>k</em>. Subtract 3 from both sides:

k^2-5k+4=0

Factor:

(k-1)(k-4)=0

Zero Product Property:

k-1=0\text{ or } k-4=0

Solve:

k=1\text{ or } k=4

So, either of the two expressions:

(x^2+5x+7)\div(x+1)\text{ or } (x^2+5x+7)\div(x+4)

Will yield 3 as the remainder.

5 0
3 years ago
Can someone sub to my youttube channel pls, its called Yakobu, it would really help out :)
mestny [16]

Answer:

yea i will what do u do ther???

Step-by-step explanation:

ohhhh gamer

6 0
3 years ago
1. For each event, write the sample space and tell how many outcomes there are.
kozerog [31]

Answer:

A. 14

Step-by-step explanation:

6 0
2 years ago
Find the lengths of x <br><br> I tried everything I still got it wrong
Arlecino [84]

if the degrees in this triangle are truly 90-45-45, then the two unknown lengths are the same

and the pythagorean theorem holds anyways: a² + b² = c², where c is the longest side in a right triangle.

c is 16, so 16² is 256

2* a² = 256

I wrote 2 times s because a and b are of same length

devide each side by 2

a² = 128

take the root

a and b are:

\sqrt{128}  = 11.31378499

7 0
2 years ago
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