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Lapatulllka [165]
3 years ago
15

3x-9=23-5x what is these?

Mathematics
2 answers:
Bas_tet [7]3 years ago
7 0
Hope this helps you..!!!

Anvisha [2.4K]3 years ago
6 0

3x - 9 = 23 - 5x

Note the equal sign. What you do to one side, you do to the other.

Isolate the x. First Add 5x to both sides, and add 9

3x (+5x) - 9 (+9) = 23 (+9) - 5x (+5x)

3x + 5x = 23 + 9

Combine like terms

8x = 32

Simplify. Isolate the x. Divide 8 from both sides

8x/8 = 32/8

x = 32/8

x = 4

4 is your answer for x.

hope this helps

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Step-by-step explanation:

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Order the following fractions and decimals from least to greatest. 1\5 ,0.83 ,3/10 ,0.03 ,5/8 ,1/3
8_murik_8 [283]

0.03, 1/5, 3/10, 1/3, 5/8, 0.83

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There are a total of 24 people at Camp Float-Away. If 4 of the people are counselors, what is the ratio of campers to counselors
pychu [463]

Answer:

5:1

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PLEASE HELP WITH MATH!
yawa3891 [41]
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8 0
3 years ago
Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi
adoni [48]

Answer:

r = 4

The center is:

(2, -4)

Step-by-step explanation:

We have the following equation

x^2 - 4x + y^2 + 8y = -4

The general equation of a circle has the following form

(x-h)^2 + (y-k)^2 = r^2

Where r is the radius and the point (h, k) is the center of the circle

To transform the given equation in the general equation of a circumference we must use the method of square completions

Step 1

(x^2 - 4x) + (y^2 + 8y) = -4

<u>Step 2</u>

<u> </u>Add and subtract (\frac{b}{2})^2 For an equation of the form

ax^2 +bx +c

(x^2 - 4x +4)-4 + (y^2 + 8y +16) -16= -4

<u>Step 3  </u> Factor the expressions within the parentheses

(x-2)^2-4 + (y+4)^2 -16= -4

<u>Step 4 Simplify</u>

(x-2)^2 + (y+4)^2= -4+16+4

(x-2)^2 + (y+4)^2= 4^2

Finally

r = 4

The center is:

(2, -4)

7 0
3 years ago
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