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3 years ago

Is the answer A B C or D

Mathematics

1 answer:

photoshop1234 [79]3 years ago

8 0

Answer:

B 86.54%

Step-by-step explanation:

There are 156 suv's

135 are driven by women

135/156 =.86538 = 86.54%

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Jane is the regional manager of Graphic DesignWorks. She earns an annual

laila [671]

Answer:

A. $16,500

Step-by-step explanation:

82500/5

8 0

3 years ago

Pleaseeee helppppppppp meeeeee

Lera25 [3.4K]

Answer:

x = 10 yd

Explanation:

These triangles are based on proportions. 12 yd is proportional to 18 yd, and <em>x </em>yd to 15 yd. We want to find <em>x</em>. We'll use the rule of three to calculate the unknown number.

12/18 = x/15

x = (12 · 15)/18

x = 10 yd (10 yards from the hut to the gold coins)

3 0

3 years ago

Amy and her sister are making lemonade for the school dance. Their recipe makes 2 quarts of lemonade. If a serving of lemonade i

Elden [556K]

Answer:

17.5

Step-by-step explanation:

6 0

4 years ago

Sec (90 -A) sinA = cot (90-A). tan( 90- A)

djyliett [7]

Step-by-step explanation:

sec(90-A) . Sin A = cot (90-A) . tan(90-A)

cosec X sinA = tanA X cotA

1/sinA X sinA = tanA X 1/tanA

1=1

Hence proved

3 0

3 years ago

Read 2 more answers

Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)

Xelga [282]

Answer:

$\frac{x^2}{16}-\frac{b^2}{4}=1$

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4$

The foci c is at +/-2√5, using c² = a² + b²:

$c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2$

Substituting the value of a and b to get the equation of the hyperbola:

$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1$

5 0

3 years ago

Is the answer A B C or D​

Is the answer A B C or D