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Alex17521 [72]
2 years ago
11

Which lists all the integer solutions of the equation |x| <3

Mathematics
1 answer:
wlad13 [49]2 years ago
7 0

Answer:

c -2 -1 0 1 and 2

Step-by-step explanation:

abs (x) < 3

Absolute value equations have 2 solutions, one positive and one negative ( remember to flip the inequality when taking the negative solution).

x<3 and x>-3

-3 <x<3

The integer solutions are -2,-1,0,1-2

We do not include 3 because there is no equals sign on the inequality.


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How much money is 15% of $14.90<br> SHOW YOUR WORK
Amiraneli [1.4K]

Answer:

The final price will be $12.67

Step-by-step explanation:

Discount = Original Price x Discount %/100

Discount = 14.9 × 15/100

Discount = 14.9 x 0.15

You save = $2.24

Final Price = Original Price - Discount

Final Price = 14.9 - 2.235

Final Price = $12.67

hope this helps and is right. p.s. i really need brainliest :)

4 0
2 years ago
Hello, can anyone help, please?
vazorg [7]

Answer:  dude you can do this yourself.

Step-by-step explanation:

toss coins ;-;

6 0
2 years ago
True or false: the equation tan^2x+1=sec^2x
zhenek [66]

ANSWER

True

EXPLANATION

The given trigonometric equation is:

{ \tan}^{2} x + 1 = { \sec}^{2} x

We take the LHS and simplify to arrive at the RHS.

{ \tan}^{2} x + 1 =  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}  + 1

Collect LCM on the right hand side to get;

{ \tan}^{2} x + 1 =  \frac{{ \sin}^{2} x + {\cos}^{2} x}{{ \cos}^{2} x}

This implies that

{ \tan}^{2} x + 1 =  \frac{1}{{ \cos}^{2} x} .

{ \tan}^{2} x + 1 =  {( \frac{1}{ \cos(x) }) }^{2}

{ \tan}^{2} x + 1 =  { \sec}^{2} x

This identity has been verified .Therefore the correct answer is true.

3 0
2 years ago
URGENT!!! PLEASE HELP!!! It doesn't have to be detailed!!!
harina [27]
4 and 1/4 feet is your answer my friend
3 0
3 years ago
(2x+3)²=5.find the roots of the equation ​
bija089 [108]

Answer:

-2.61803398875, -0.38196601125

or

(-3±√5)/2

Step-by-step explanation:

First, expand. (2x+3)² = 4x²+12x+9=5

4x²+12x+4 = 0

Quadratic equations take the form ax²+bx+c = 0

In this case,

a = 4

b = 12

c = 4

You can solve with the equation x=(-b±√b²-4ac)/2a

Plug in:

(-12±√144-64)/8

(-12±√80)/8

(-12±√2^4×5)/8

(-12±4√5)/8

(-3±√5)/2

Final answer x = (-3±√5)/2

If you want decimal form: -2.61803398875, -0.38196601125

4 0
2 years ago
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