ANSWER: B)198
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Answer:
<em>See above photograph</em>
Step-by-step explanation:
This is how your graph will look like with an x-intercept of [−5, 0] (will not see, according to the scale, but on my device, you can), and a y-intercept of [0, 50]. The way to figure out all the coordinates upon this scale is to simply create a y-x value chart. Plug in each input value [x-value] to get your output value [y-value]:
<u>x|y</u>
0|50
1|60
2|70
3|80
4|90
5|100
6|110
7|120
8|130
9|140
10|150
11|160
Then, you simply just draw your line based of this chart.
I am joyous to assist you anytime.
It's false. It's a product so...
Derivative of the first TIMES the second PLUS derivative of second TIMES the first.
Derivative of the first (x^3) = 3x^2
Times the second = 3x^2 * e^x
Derivative of the second = e^x (remains unchanged)
Times the first = e^x * x^3
So the answer would be (3x^2)(e^x) + (e^x)(x^3)
which can be factorised to form x^2·e^x(3 + x)