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sergejj [24]
3 years ago
12

A photograph is taken by letting light fall on a light-sensitive medium, which then records the image onto that medium.

Computers and Technology
2 answers:
Naddik [55]3 years ago
6 0

Answer: The answer is True

Explanation: I took the test and this answer was right

Andru [333]3 years ago
4 0
True. At least that's how it is for camera's that print photos. Not digital cameras
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Create the following new exceptions: PokemonException, which extends the Exception class. It must have a no-parameter constructo
slamgirl [31]

Answer:

public class PokemonException extends Exception {

public PokemonException() {

super();

}

}

public class KantoPokemonException extends PokemonException {

public KantoPokemonException() {

super();

}

}

public class JohtoPokemonException extends PokemonException {

public JohtoPokemonException() {

super();

}

}

public class HoennPokemonException extends PokemonException {

public HoennPokemonException() {

super();

}

}

public class SinnohPokemonException extends PokemonException {

public SinnohPokemonException() {

super();

}

}

public class UnovaPokemonException extends PokemonException {

public UnovaPokemonException() {

super();

}

}

public class KalosPokemonException extends PokemonException {

public KalosPokemonException() {

super();

}

}

public class AlolaPokemonException extends PokemonException {

public AlolaPokemonException() {

super();

}

}

public class GalarPokemonException extends PokemonException {

public GalarPokemonException() {

super();

}

}

Explanation:

  • A separate Java file needs to be created for each of the following exception.
  • Inside the constructor, call the super() method to inherit all the properties of a parent class.
6 0
3 years ago
which one of the following will reach every element in the array a? 1. for(int i = 0; i <= a.length; i++) 2. for(int i = 0; i
andrey2020 [161]

Answer:

You can simplify the problem down by recognizing that you just need to keep track of the integers you've seen in array that your given. You also need to account for edge cases for when the array is empty or the value you get would be greater than your max allowed value. Finally, you need to ensure O(n) complexity, you can't keep looping for every value you come across. This is where the boolean array comes in handy. See below -

public static int solution(int[] A)

{

int min = 1;

int max = 100000;

boolean[] vals = new boolean[max+1];

if(A.length == 0)

return min;

//mark the vals array with the integers we have seen in the A[]

for(int i = 0; i < A.length; i++)

{

if(A[i] < max + 1)

vals[A[i]] = true;

}

//start at our min val and loop until we come across a value we have not seen in A[]

for (int i = 1; i < max; i++)

{

if(vals[i] && min == i)

min++;

else if(!vals[i])

break;

}

if(min > max)

return max;

return min;

}

4 0
1 year ago
When constructing policies regarding data _______________, it is important that these policies offer particular guidance on sepa
Rama09 [41]

Answer:

access

Explanation:

Managing users' access rights to digital resources within the organization's environment is a fundamental SoD control. As more services are requested by users, utilizing the built-in panels to check compliance with internal controls might become excessive. Companies require a comprehensive Identity Governance and Administration plan to monitor these user access and offer an authoritative source of identity definitions in order to ensure  SoD compliance.

6 0
2 years ago
Your wireless network consists of multiple 802.11n access points that are configured as follows: SSID (hidden): CorpNet Security
nasty-shy [4]

Answer:

double the bandwidth assigned per channel to 40 MHz

Explanation:

The best way of doing this would be to double the bandwidth assigned per channel to 40 MHz. This will make sure that the capacity is more than sufficient. This is simply because the bandwidth of a channel represents how much information can pass through the channel at any given second, the larger the channel, the more information/data that can pass at the same time. Therefore, if 20 MHz is enough for the network, then doubling this bandwidth channel size would be more than sufficient capacity for the network to handle all of the data.

6 0
2 years ago
All of the following are parts of the word processing window except _____. \
Rainbow [258]
<span>All of the following are parts of the word processing window except for the button esc ____.</span>
5 0
3 years ago
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