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Nady [450]
3 years ago
11

(Math Plato) Drag the tiles to the correct boxes to complete the pairs. Solve the inequalities for x, and match each solution to

its number line graph.​

Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

1. 0.82x

2. 1.18x

3. \dfrac{7}{10}x

4. \dfrac{13}{10}x

Step-by-step explanation:

1. List price = \$x

  Discount = 18%

  New price =\$x-0.18\cdot \$x=\$0.82x

2. Amount needed to build the toy =\$x

   Add = 18%

   Selling price =\$x+0.18\cdot \$x=\$1.18x

3. Initial volume of water =x

   Fraction drained =\dfrac{3}{10}

   Fraction left =1-\dfrac{3}{10}=\dfrac{7}{10}

   Volume lext =\dfrac{7}{10}x

4. Initial amount =x

   Fraction received =\dfrac{3}{10}

   Final fraction =1+\dfrac{3}{10}=\dfrac{13}{10}

   Final amount =\dfrac{13}{10}x

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Arlecino [84]

Answer:

66

Step-by-step explanation:

6 0
3 years ago
Solve for x. + 6 = 10 4 1 16 64
Alecsey [184]

Answer: First, turn the mixed fraction 16 1/4 into a improper fraction. It would become 65/4

x+65/4=64

Next, I would multiply the entire equation by 4 to get rid of the fraction

It would become 4x+65=256

Now solve for X

4x=191

x=191/4

x=47.75

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
(9x−2.25)=(1.6+9x)<br><br> help
mel-nik [20]
Begin solving like you normally would. Add 2.25 to both sides and subtract 9x from both sides to try getting all x values on one side. However, you will find that after subtracting 9x from both sides, all x values go away, and you end with -2.25=1.6. This is not true (-2.25 is not 1.6), so the answer is no solution. There is no value of x which satisfies that equation.
4 0
3 years ago
Bought three boxes totaling 151 book cost 50% more than the other two what was the price of the more expensive book 80 85 90 95
GenaCL600 [577]
Two cheaper books = x
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so, 2.5x=150
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7 0
3 years ago
QUESTION
Lorico [155]
1. For this item we just refer to the prompt to know the conjectures of Ernest and Denise. According to Ernest, they should swim 1 kilometer on the first week then add 0.25km every week while Denise believes that they should swim 1 kilometer on the first week then add 0.5km every week.

2. Yes, these distances make an arithmetic sequence. It's because an arithmetic sequence is defined as a group of increasing or decreasing numbers where the difference between any two consecutive numbers is constant. This just means that every number has the same interval. In the case of their schedule, this is true.

3. For this item we just follow the descriptions of Ernest's and Denise's schedule in item number 1. For Ernest, we just keep adding 0.25 from 1 kilometer until we added it thrice. For Denise, we also keep adding a number thrice but this time it's 0.5 instead of 0.25.

Ernest's Schedule: 1, 1.25, 1.5, 1.75
Denise's Schedule: 1, 1.5, 2, 2.5

4. Here we are asked to determine a formula that will describe the schedules of Ernest and Denise. In the given formula a_{n}= a_{n-1}+d, a_{n} refers to the next term in the sequence, a_{n-1} refers to the previous term, while d refers to the common difference. In the recursive formula all we need is to insert the value of d to the equations.

Ernest: a_{n}= a_{n-1}+0.25
Denise: a_{n}= a_{n-1}+0.5

5. For this item we basically do the same thing but this time we are given another formula. Our formula is in the form a_{n}= a_{1}+(n-1)d where a_{n} is still the nth term of the sequence, a_{1} is the very first time, n is the number of terms, and d is the common difference. 

Ernest: a_{n}= 1.0+0.25(n-1)
Denise: a_{n}= 1.0+0.5(n-1)

6. In this item we will just basically substitute numbers to one of the equations that we've set up in item #5. For this we need Ernest's explicit formula first. To know how far they will be swimming on week 10, the number of elements (n) must be 10.

a_{10}= 1.0+0.25(10-1)
a_{10}= 1.0+0.25(9)
a_{10}= 1.0+2.25
a_{10}= 3.25

7. Here, we just do the same thing as item #6 but this time we will consider Denise's explicit formula. Since we are also asked how far the students will be swimming on week 10, the number of elements would also be 10 and this would also be our value for n.

a_{10}= 1.0+0.5(10-1)
a_{10}= 1.0+0.5(9)
a_{10}= 1.0+4.5
a_{10}= 5.5

8. The answer for this question is obvious. You would just need to look at the 10th element in Ernest's and Denise's sequences and tell whose schedule had more than or equal to 5 as an answer. Following Ernest's schedule, you will just get 3.5 kilometers on the 10th week so it's definitely a no. Denise's schedule, on the other hand, would get you to 5.5 kilometers on week 10 so her training schedule should be followed.
7 0
3 years ago
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