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Yanka [14]
3 years ago
9

If there were 300 accidents in 1967 and 380 in 1968, what is the percent increase?

Mathematics
2 answers:
Jet001 [13]3 years ago
4 0

Answer:

As per the statement:

If there were 300 accidents in 1967 and 380 in 1968.

Number of accident in 1967= 300

Number of accident in 1968= 380

then;

Increase in accident = 380-300 = 80

Using formula to find the percent increase:

\text{Increase in percent} = \frac{\text{Increase in accident}}{\text{Number of accident in 1967}} \times 100

Substitute the given values we have;

\text{Increase in percent} = \frac{80}{300} \times 100

Simplify:

\text{Increase in percent} = \frac{80}{3} = 26\frac{2}{3} \%

Therefore, 26\frac{2}{3} \%  is the percent increase

VikaD [51]3 years ago
3 0
First find the amount of increase: 380-300=80. Then divide the amount of increase by the original amount: 80/300=.266666667. Normally you round to the tenths place: .27. Then make it a percent: .27=27%. The percent of increase is 27% :) hope this helps
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By concepts of polynomials and systems of linear equations, the constants c and d of the expression p(x) = x⁴ - 5 · x³ - 7 · x² + c · x + d are 29 and 30.

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