Answer:
$240.00 is the monthly interest
Answer:
x = 2
Step-by-step explanation:
the formula for this problem is
Area = 1/2 base x Height
step 1) plug in what we know
5 = 1/2 base(5)
step 2) switch sides
1/2 base x 5 = 5
step 3) divide both sides by 1/2 x 5
= ![\frac{5}{1/2(5)}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B1%2F2%285%29%7D)
step 4) Simplify
![\frac{1/2 base (5)}{1/2 (5)}: b](https://tex.z-dn.net/?f=%5Cfrac%7B1%2F2%20base%20%285%29%7D%7B1%2F2%20%285%29%7D%3A%20b)
step 5) Simplify
![\frac{5}{1/2(5)}: 2](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B1%2F2%285%29%7D%3A%202)
step 6) now you have gotten the answer<u> x = 2</u>
find the mean, median, and interquartile range for the data set below. 5,8,9,11,13,15,16,17,17,18,22,23
Alekssandra [29.7K]
Answer:
Mean: 14.5
Median: 15.5
IQR = 7.5
Step-by-step explanation:
For mean:
Mean= (∑x)/n
=(5+8+9+11+13+15+16+17+17+18+22+23)/12
= 174/12
=14.5
Median:
As the data is already sorted and the number of items are odd, average of two middle values will be the median of the data.
5,8,9,11,13,15,16,17,17,18,22,23
Median=(15+16)/2
=31/2
=15.5
IQR:
For IQR, the data has to be divided in two parts, lower and upper, then we have to find the median of both parts separately. The difference of medians of both parts is called the Interquartile range.
So for lower part,
5,8,9,11,13,15
Median for lower part= (9+11)/2
= 20/2
=10
For upper part:
16,17,17,18,22,23
Median for lower part= (17+18)/2
= 35/2
=17.5
IQR=17.5-10
=7.5
It’s 36 I looked it up and I did this before have a good day anything else?