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Komok [63]
3 years ago
13

In a(n) _________ program a student must pass an exam at the end of the course with a 3out if 5 in order to get college credit.

Some colleges require even higher scores or they will not accept the credit
Computers and Technology
2 answers:
s2008m [1.1K]3 years ago
8 0
Advanced placement should be the answer
zlopas [31]3 years ago
7 0

Answer:

Its an AP program.

Explanation:

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Router 1 is configured with static NAT. Addressing on the router and the web server are correctly configured, but there is no co
marin [14]

Answer:

The router NAT configuration has an incorrect inside local address.

Explanation:

The term Inside in a <em>Network Address Translation (NAT) </em>context refers to networks owned by an organisation that must be translated. When NAT is configured, hosts within this network have addresses in one space (known as the local address space). These hosts appear to those users outside the network as being in another space (known as the global address space).

The term Outside refers to those networks to which the stub network connects, and which are not under the control of an organisation. Also, hosts in outside networks can be subject to translation, and can thus have local and global addresses

7 0
3 years ago
How is ict integrated into marketing<br>​
Aleks04 [339]

Answer: The utilize of great ICT moreover moves forward client administrations and client request. From database advancement, site plan to showcase investigate, interpretation program, coordinate mail showcasing and preparing, the application of ICT is basic for a financial victory. The web is one of the ways in which media companies / businesses publicize.

Explanation:

5 0
2 years ago
What is the name of the computer through which e-mail messages are sent and received?
nalin [4]
A mail server. --------------------------------------------
8 0
3 years ago
Suppose a program takes 1000 machine instructions to run from start to end, and can do that in 10 microseconds when no page faul
Tema [17]

Answer:

(10^6 + 9.9)

Explanation:

Given:

Total number of machine instructions = 1000

Number of page fault in 100 instructions = 1

Number of page faults in 1000 instructions = 10

Time to serve one page fault = 100 milliseconds

Time to serve ten page faults = 100*10 milliseconds = 1000 milliseconds = 10^6 Microseconds

Number of instructions without any page fault = 1000 - 10 = 990

Time required to run 1000 instructions = 10 Microseconds

So, time required to run 990 instructions = (10*(990/1000)) Microseconds = 9.9 Microseconds

So, the total time required to run the program = (10^6 + 9.9) Microseconds

3 0
4 years ago
Which selection below has the greatest storage capacity
shutvik [7]
Where is the selection?

Message me when you have the full question.
8 0
3 years ago
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