So 5,10,15,20,25,30,35,40,45 so Aylson needs 1 more bead. Because 45 beads are already used!
a. (2175 mi)/(18 mi/day) = 120.83... day ≈ 121 days
b. 120.83.../4 = 30.2083...
Joelle will hike 30 full days and one partial day.
After graphing the lines, you can see that the solution is (4, -1)
Step-by-step explanation:
√a = 1√a so we can solve them easily:
b) 3√7 -√7= 3√7 - 1√7 =( 3-1)√7= 2√7
d) 5√6 - 2√6+√6= (5-2+1)√6 = 4√6
g) √2+2√2= 3√2
j) √5+5√5 - 3√5 = 3√5
k) 2√3 + √3 - 5√3= -2√3
I) 5√11 + 7√11 - √11 = 11√11
Answer:
<u>Infotron should produce each day 13 hockey and 6 soccer games</u>
Step-by-step explanation:
x = Number of hockey games Infotron should produce
y = Number of soccer games Infotron should produce
Number of labor-hours for assembly = 2x + 3y
Number of labor-hours for testing = 2x + y
Now we can write our equations system, this way:
2x + 3y = 44
2x + y = 32
*********************
Expressing y in terms of x in the 2nd equation:
2x + y = 32
y = 32 - 2x
********************
Substituting y and solving for x in the 1st equation:
2x + 3y = 44
2x + 3 * ( 32 - 2x) = 44
2x + 96 - 6x = 44
-4x = 44 - 96
-4x = - 52
x = -52/-4
x = 13
*****************
Solving for y in the 2nd equation:
2x + y = 32
2 * 13 + y = 32
26 + y = 32
y = 32 - 26
y =<u> 6</u>
<u>Infotron should produce each day 13 hockey and 6 soccer games</u>
